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laiz [17]
3 years ago
13

When Zack checked his solution, it didn’t work. What was his mistake?

Mathematics
2 answers:
raketka [301]3 years ago
8 0

Answer:

where is the solution?? maybe a careless mistake

Step-by-step explanation:

KatRina [158]3 years ago
4 0

Answer:

he whent up and not down and left and not right

Step-by-step explanation:we just is messed up in life

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Sum of the interior angles of any triangle is 180° .

Thus ;

y + 48° + 90° = 180°

y + 138° = 180°

Subtract sides 138°

y + 138° - 138° = 180° - 138° \\

y = 42°

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4 0
3 years ago
For an angle Θ with the point (12, −5) on its terminating side, what is the value of cosine?
Pachacha [2.7K]
Given that the point (12,-5) which takes the form (x,y), This implies that:
opposite=-5
adjacent=12
thus using using Pythagorean theorem, the hypotenuse will be:
c^2=a^2+b^2
plugging the values we obtain:
c^2=(12)^2+(-5)^2
c^2=144+15
c^2=169
thus
c=13
but
cos θ=adjacent/ hypotenuse
therefore:
cos θ=12/13

Answer is option . D
5 0
3 years ago
The vertex of this parabola is at (-4, -1). When the y-value is 0, the x-value is 2. What is the coefficient of the squared term
satela [25.4K]
\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
y=a(x-(-4))^2-1\implies y=a(x+4)^2-1
\\\\\\
\textit{now, we also know that }
\begin{cases}
y=0\\
x=2
\end{cases}\implies \underline{0}=a(\underline{2}+4)^2-1

solve for "a"
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3 years ago
Are the triangles similar? explain. please help
grin007 [14]

Answer:

The triangles are similar.

Step-by-step explanation:

The reason for this is because they both share two pairs of angles that are the same: 40 degrees and 60 degrees. If these are equal, then that must mean the third angle for both triangles is also the same, making both triangles equal in proportion. Therefore, they must be similar.

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Step-by-step explanation:

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