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Reika [66]
2 years ago
14

Help me finish my delta maths

Mathematics
1 answer:
otez555 [7]2 years ago
8 0

Answer:

work on your English first

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(a²b²-c²)(a²b²+c²)<br>simplify​
liraira [26]

Answer:

a⁴b⁴ - c⁴

Step-by-step explanation:

The difference of squares formula states that (a - b)(a + b) = a² - b². In this case, a = a²b² and b = c² so a² - b² = (a²b²)² - (c²)² = a⁴b⁴ - c⁴.

6 0
3 years ago
Read 2 more answers
14/38 simplified? Thanks!
ira [324]
14/38 simplified would be 7/19
5 0
3 years ago
Which points are coplanar?<br> A. C,G,A,F<br> B. A,J,K,I<br> C. B,J,K,F<br> D. A,B,H,G
Damm [24]

Answer:

B, J, K, F. Because they are on the same side compared to the other answers.

Step-by-step explanation:

Coplanar points are three or more points which all lie in the same plane. Any set of three points in space is coplanar. A set of four points may be coplanar or may be not coplanar.

Plz mark brainliest!

4 0
2 years ago
Consider the line y = 2x–4.
choli [55]

Parallel slope = 2

This is because the original line has slope 2. Parallel lines have equal slopes.

--------------------------

Perpendicular slope = -1/2

The original slope 2 or 2/1 turns into -1/2 after flipping the fraction and the sign. Note the original slope and perpendicular slope multiply to -1. This is true for any pair of perpendicular lines where neither line is vertical.

8 0
2 years ago
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Medical scientists study the effect of acute infection on tissue-specific immunity. In a collection of experiments under the sam
Serjik [45]

Answer:

The 95% confidence interval  for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

In a collection of experiments under the same conditions, 44 of 75 mice test positive for lymphadenopathy. This means that n = 75 and \pi = \frac{44}{75} = 0.586.

Compute a 95% confidence interval for the true proportion of mice that will test positive under similar conditions.

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 - 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.5291

The upper limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 + 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.6429

The 95% confidence interval  for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

7 0
2 years ago
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