The Fibonacci sequence 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, … is formed by summing two consecutive numbers to get the next number.
adelina 88 [10]
By counting the combinations, we will see that there are 10 combinations such that the sum gives a Fibonacci number.
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How to count the combinations?</h3>
We have two number cubes with 6 outcomes each, such that we have a total of 36 combined outcomes.
For each dice, the outcomes are:
{1, 2, 3, 5, 8, 13}
Now, let's count the combinations that also give a Fibonacci number (these are given by adding two consecutive numbers in the sequence).
I will list each possible red outcome, then the blue outcomes that would give a Fibonacci term, and then we can count the number of combinations.
- Red Blue number of combinations.
- 1 2 1
- 2 1, 2 2
- 3 2, 3 2
- 5 3, 8 2
- 8 5, 13 2
- 13 8 1
Adding the numbers of combinations, we have:
C = 1 + 2 + 2 + 2 + 2 + 1 = 10
There are 10 combinations that give a Fubbonaci number.
If you want to learn more about combinations, you can read:
brainly.com/question/2280026
F(x) = x + 2
when x = 1, f(1) = 1 + 2 = 3
Therefore range for x ≠ 1 is y ≠ 3.
-6.25 is the value of p. First distribute the 8 to the parentheses and then solve the equation
