Answer:
100 times everything.
Step-by-step explanation:
If the cow is 100 times larger than its normal size, obviously everything else should be 100 times stronger and heavier.
Answer:
a.
![Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936](https://tex.z-dn.net/?f=Month%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20Pop%28whole%20%5C%20ant%29%5C%5Cmonth1%20%3D%3E%20x_1%3D80%5Ctimes0.94%5E1%3D1128%5C%5Cmonth2%3D%3Ex_2%3D1200%5Ctimes0.94%5E2%3D1060%5C%5Cmonth3%3D%3Ex_3%3D1200%5Ctimes0.94%5E3%3D996%5C%5Cmonth4%3D%3Ex_4%3D1200%5Ctimes0.94%5E4%3D936)
b.
![week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g](https://tex.z-dn.net/?f=week%20Number%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20Mass%28g%29%5C%5Cweek1%20%3D%3E%20x_1%3D80%5Ctimes1.1%5E1%3D88g%5C%5Cweek2%3D%3Ex_2%3D80%5Ctimes1.1%5E2%3D96.8g%5C%5Cweek3%3D%3Ex_3%3D80%5Ctimes1.1%5E3%3D106.48g%5C%5Cweek4%3D%3Ex_4%3D80%5Ctimes1.1%5E4%3D117.128g)
Step-by-step explanation:
a. From the information provided, we can deduce that the population death's follows a Geometric sequence in the form
where
and ![r-common \ ratio](https://tex.z-dn.net/?f=r-common%20%5C%20ratio)
#Since the population is reducing,
can is obtained as ![r=1-r=0.94](https://tex.z-dn.net/?f=r%3D1-r%3D0.94)
#The
term is obtained using the formula
, given a=1200
The number of ants alive after every month (in first 4 months)
![Month\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Pop(whole \ ant)\\month1 => x_1=80\times0.94^1=1128\\month2=>x_2=1200\times0.94^2=1060\\month3=>x_3=1200\times0.94^3=996\\month4=>x_4=1200\times0.94^4=936](https://tex.z-dn.net/?f=Month%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20Pop%28whole%20%5C%20ant%29%5C%5Cmonth1%20%3D%3E%20x_1%3D80%5Ctimes0.94%5E1%3D1128%5C%5Cmonth2%3D%3Ex_2%3D1200%5Ctimes0.94%5E2%3D1060%5C%5Cmonth3%3D%3Ex_3%3D1200%5Ctimes0.94%5E3%3D996%5C%5Cmonth4%3D%3Ex_4%3D1200%5Ctimes0.94%5E4%3D936)
The ant's alive after 4 months is obtained as the value of ![x_5](https://tex.z-dn.net/?f=x_5)
![x_n=ar^(^n^-^1^)\\1-x_5=1-1200\times 0.94^4=936.89\\\approx 936](https://tex.z-dn.net/?f=x_n%3Dar%5E%28%5En%5E-%5E1%5E%29%5C%5C1-x_5%3D1-1200%5Ctimes%200.94%5E4%3D936.89%5C%5C%5Capprox%20936)
Hence, 936 ants are alive after 4 months.
b. As with the above question, the kitten population follows a geometric sequence:
.
#Since it's a growing population , the common ration is the sum of 100% + the growth rate,
and
and ![x_n=ar^(^n^-^1^)](https://tex.z-dn.net/?f=x_n%3Dar%5E%28%5En%5E-%5E1%5E%29)
The population after 4weeks will be:
![week Number\ \ \ \ \ \ \ \ \ \ \ \ \ \ Mass(g)\\week1 => x_1=80\times1.1^1=88g\\week2=>x_2=80\times1.1^2=96.8g\\week3=>x_3=80\times1.1^3=106.48g\\week4=>x_4=80\times1.1^4=117.128g](https://tex.z-dn.net/?f=week%20Number%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20Mass%28g%29%5C%5Cweek1%20%3D%3E%20x_1%3D80%5Ctimes1.1%5E1%3D88g%5C%5Cweek2%3D%3Ex_2%3D80%5Ctimes1.1%5E2%3D96.8g%5C%5Cweek3%3D%3Ex_3%3D80%5Ctimes1.1%5E3%3D106.48g%5C%5Cweek4%3D%3Ex_4%3D80%5Ctimes1.1%5E4%3D117.128g)
The amount gotten after $1689 invested for 4 years at 3% compounded annually is $1901
The amount of money gained after an investment is compounded is given by:
![A=P(1+\frac{r}{n} )^{nt}](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7Bnt%7D)
Where P is principal, A is the final amount, r is the rate, n is the number of times compounded per period and t is the time
Given that P = $1689, t = 4, r = 3% = 0.03, n = 1, hence:
![A=P(1+\frac{r}{n} )^{nt}\\\\A=1689(1+\frac{0.03}{1} )^{4*1}\\\\A=\$1901](https://tex.z-dn.net/?f=A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%20%29%5E%7Bnt%7D%5C%5C%5C%5CA%3D1689%281%2B%5Cfrac%7B0.03%7D%7B1%7D%20%29%5E%7B4%2A1%7D%5C%5C%5C%5CA%3D%5C%241901)
The amount gotten after $1689 invested for 4 years at 3% compounded annually is $1901
Find out more at: brainly.com/question/14295570
Answer:
Number Three
Step-by-step explanation:
27/75 equals 0.36, and that is approximate to one third. Also, I just took the edge quiz and got that question right
Answer:
10 to 15
Step-by-step explanation:
the spread is the start and stop of points data. It goes from the least point to the most point, here there is a dot (two technally) on 10 and a dot on 15 where the data stops so the data spread is 10-15