Volume of a cone, V = πr^2h/3
r = Sqrt 3V/πh = Sqrt [(58.9*3)/(3.14*9)] = 2.5 cm, minimum
Surface area, A = πr [r+ Sqrt (h^2+r^2)] = 3.14*2.5*[2.5+ Sqrt (9^2+2.5^2)] = 92.95 cm^2
Therefore, minimum amount of paper required is 92.95 cm^2
The solution is: 252. 14x18
C is the awnser I believe correct me if I’m wrong
A- 998.8×997.7=996502.76
B- 998.84×997.73=996572.6332
C- 998.843×997.731=996576.6252
D - 999×998=997002
So D is the answer
