Answer:
Step-by-step explanation:
Complementary angles mean two two angles sum with equal 90 degrees. Therefore you would need to create an equation to solve for the value of x.
4x+3x+13=90
-13 -13
7x=77
/7 /7
X=11
Now plug in the value of x.
A=4(11) B=3(11)+13
A=44. B=33+13
B=46
Angle a is the smaller angle and measures at 44°
Answer:
There are 38 premium tickets and 82 regular tickets in a pile.
Step-by-step explanation:
Given,
Total number of tickets = 120
Total amount = $5812
Solution,
Let the number of premium tickets be x.
And the number of regular tickets be y.
Total number of tickets is the sum of total number of premium tickets and total number of regular tickets.
So the equation can be written as;
Again,total amount is the sum of total number of premium tickets multiplied by cost of each premium ticket and total number of regular tickets multiplied by cost of each regular ticket.
So the equation can be written as;
Now We will multiply equation 1 by 25 we get;
Now Subtracting equation 3 from equation 2 we get;
We will now substitute the value of x in equation 1 we get;
Hence There are 38 premium tickets and 82 regular tickets in a pile.
On average a lamb weighs about 200 pounds,
so 12345678910 multiplied by 200 =<span>2.469135782e+12
</span>2.469135782e+12 divided by 2000 = <span>1234567891 tons</span>
70 x P = 63
P=63/70 = 0.9
Since P is 1-the discount
1-discount= 0.9
discount is 0.1, or 10 %
Answer:
x = 50*e∧ -t/100
Step-by-step explanation:
We assume:
1.-That the volume of mixing is always constant 300 gallons
2.-The mixing is instantaneous
Δ(x)t = Amount in - Amount out
Amount = rate * concentration*Δt
Amount in = 3 gallons/ min * 0 = 0
Amount out = 3 gallons/min * x/ 300*Δt
Then
Δ(x)t/Δt = - 3*x/300 Δt⇒0 lim Δ(x)t/Δt = dx/dt
dx/dt = - x/100
dx/ x = - dt/100
A linear first degree differential equation
∫ dx/x = ∫ - dt/100
Ln x = - t/100 + C
initial conditions to determine C
t= 0 x = 50 pounds
Ln (50) = 0/100 * C
C = ln (50)
Then final solution is:
Ln x = - t/100 + Ln(50) or
e∧ Lnx = e ∧ ( -t/100 + Ln(50))
x = e∧ ( -t/100) * e∧Ln(50)
x = e∧ ( -t/100) * 50
x = 50*e∧ -t/100
