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2 years ago

Plz help ASAP 20 points 10. What is the equation of a circle with radius, r = 4, and the center at (0,0)?

Mathematics

2 answers:

nignag [31]2 years ago

8 0

The answer that you are looking for is A. X2 + y2 = 4

Ostrovityanka [42]2 years ago

5 0

Answer:

Step-by-step explanation:

the equation for a circle centered at orgin is x^2+y^2=r where r is the radius. multiplying, adding, or subtracting any numbers to the x and y components such as the other choices here causes the circle to be translated about the graph.

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Is the square root of -11.2 a rational number?

Schach [20]

No, it is an imaginary number.
Can't take the square root of a negative number without creating a method termed an imaginary number, which is the square root of -1 which they have used " i " to signify.
Then square root of -11.2 would be written Sqrt(11.2)i. The Sqrt(11.2) = 3.3466
so the answer is 3.3466i

5 0

2 years ago

1) A medium cookies and creme milkshake at The

Leya [2.2K]

Answer:

You will pay $4.31

Step-by-step explanation:

I know this because a fourth of $5.75 is 1.4375 so you would round it to $1.44 and then $5.75 - $1.44 is $4.31.

So you will pay $4.31 for one milkshake.

5 0

2 years ago

What’s the measure of x for the for each figure?

Minchanka [31]

Answer:

a)73

b)27

c)58

d)70

6 0

3 years ago

Multiply: 5.13 × 4 ASAP correct answers only pls

balandron [24]

Answer: 20.52

Step-by-step explanation:

Your welcome

4 0

2 years ago

Find soluton to x^2-14x+49=25

Artyom0805 [142]

$\boxed{x=12 \ and \ x=2}$

<h2>Explanation:</h2>

In this exercise, we have the following equation:

$x^2-14x+49=25$

We can write this Quadratic Equation in Standard Form as follows:

$x^2-14x+49=25 \\ \\ Subtract \ 25 \ from \ both \ sides: \\ \\ x^2-14x+49-25=25-25 \\ \\ x^2-14x+24=0 \\ \\$

So this is a Non-perfect Square Trinomial. To factor out this, let's choose two numbers such that:

The sum is -14
The product is 24

Those numbers are:

-12 and -2
SUM: -12-2 = -14
PRODUCT: (-12)(-2)=24

So we can write this as:

$x^2 + (a + b)x + ab=(x + a)(x + b) \\ \\ a=-12 \\ b=-2 \\ \\ x^2-14x+24=(x-12)(x-2)=0 \\ \\ So \ the \ solutions \ are: \\ \\ \boxed{x=12 \ and \ x=2}$

<h2>Learn more:</h2>

Quadratic Ffrmua: brainly.com/question/10188317

#LearnWithBrainly

6 0

2 years ago