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s344n2d4d5 [400]
3 years ago
10

Plz help ASAP 20 points 10. What is the equation of a circle with radius, r = 4, and the center at (0,0)?

Mathematics
2 answers:
nignag [31]3 years ago
8 0
The answer that you are looking for is A. X2 + y2 = 4
Ostrovityanka [42]3 years ago
5 0

Answer:

a

Step-by-step explanation:

the equation for a circle centered at orgin is x^2+y^2=r where r is the radius. multiplying, adding, or subtracting any numbers to the x and y components such as the other choices here causes the circle to be translated about the graph.

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3 years ago
The entire question is un the picture
n200080 [17]
A) 6x -5y = 5
B) 3x + 5y = 4
Adding the equations:
9x = 9
x = 1

A) 6*1 -5y = 5
A) 6 - 5 = 5y
A) 5y = 1
y = 1/5 = .2


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3 years ago
Is this correct? Bowmanian
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3 years ago
The midpoint of line CD is M(-3,-7). If the coordinates of C are (-2, -10), what are the coordinates of D?
Lynna [10]

Answer:

D = (-4, -4)

Step-by-step explanation:

Given;

midpoint of line CD = M(-3, -7)

coordinate of C = (-2, -10)

The coordinate of D is calculated as follows;

C(-2, -10)---------------------M(-3, -7)--------------------D

M = \frac{D_1 + C_1}{2} \ , \ \frac{D_2 + C_2}{2} \\\\(-3, \ -7) = \frac{D_1 + (-2)}{2} , \ \frac{D_2 + (-10)}{2} \\\\(-3, \ -7) = \frac{D_1 \ - \ 2}{2} , \ \frac{D_2 -10}{2} \\\\-3 =  \frac{D_1 \ - \ 2}{2}  \ \ ----(1)\\\\-7 =  \frac{D_2 -10}{2}  \ -----(2)\\\\From \ (1): 2(-3) = D_1\ - \ 2\\\\-6 = D_1 - 2\\\\-6 + 2 = D_1\\\\-4 = D_1\\\\From \ (2) : \ 2(-7) = D_2 - 10\\\\-14 = D_2 - 10\\\\ -14 + 10 = D_2\\\\-4 = D_2\\\\The \ coordinate \ of \ D = (D_1\ , \ D_2)\\\\D = (-4 \ , \ -4)

Therefore, the coordinate of D = (-4, -4)

6 0
3 years ago
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