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stellarik [79]
2 years ago
11

Miss logan leaves school at 15:55 it takes her 1 hour and 20 mins to get home what time does she arrive home? answer using 24 ho

ur time​
Mathematics
1 answer:
cluponka [151]2 years ago
6 0

Answer:

5:15

Step-by-step explanation:

15:55 = 3:55 in normal time

3:55 + 1 hr = 4:55

4:55 + 20 min = 5:15

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The mean number of words per minute (WPM) read by sixth graders is 8888 with a standard deviation of 1414 WPM. If 137137 sixth g
Bingel [31]

Noticing that there is a pattern of repetition in the question (the numbers are repeated twice), we are assuming that the mean number of words per minute is 88, the standard deviation is of 14 WPM, as well as the number of sixth graders is 137, and that there is a need to estimate the probability that the sample mean would be greater than 89.87.

Answer:

"The probability that the sample mean would be greater than 89.87 WPM" is about \\ P(z>1.56) = 0.0594.

Step-by-step explanation:

This is a problem of the <em>distribution of sample means</em>. Roughly speaking, we have the probability distribution of samples obtained from the same population. Each sample mean is an estimation of the population mean, and we know that this distribution behaves <em>normally</em> for samples sizes equal or greater than 30 \\ n \geq 30. Mathematically

\\ \overline{X} \sim N(\mu, \frac{\sigma}{\sqrt{n}}) [1]

In words, the latter distribution has a mean that equals the population mean, and a standard deviation that also equals the population standard deviation divided by the square root of the sample size.

Moreover, we know that the variable Z follows a <em>normal standard distribution</em>, i.e., a normal distribution that has a population mean \\ \mu = 0 and a population standard deviation \\ \sigma = 1.

\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}} [2]

From the question, we know that

  • The population mean is \\ \mu = 88 WPM
  • The population standard deviation is \\ \sigma = 14 WPM

We also know the size of the sample for this case: \\ n = 137 sixth graders.

We need to estimate the probability that a sample mean being greater than \\ \overline{X} = 89.87 WPM in the <em>distribution of sample means</em>. We can use the formula [2] to find this question.

The probability that the sample mean would be greater than 89.87 WPM

\\ Z = \frac{\overline{X} - \mu}{\frac{\sigma}{\sqrt{n}}}

\\ Z = \frac{89.87 - 88}{\frac{14}{\sqrt{137}}}

\\ Z = \frac{1.87}{\frac{14}{\sqrt{137}}}

\\ Z = 1.5634 \approx 1.56

This is a <em>standardized value </em> and it tells us that the sample with mean 89.87 is 1.56<em> standard deviations</em> <em>above</em> the mean of the sampling distribution.

We can consult the probability of P(z<1.56) in any <em>cumulative</em> <em>standard normal table</em> available in Statistics books or on the Internet. Of course, this probability is the same that \\ P(\overline{X} < 89.87). Then

\\ P(z

However, we are looking for P(z>1.56), which is the <em>complement probability</em> of the previous probability. Therefore

\\ P(z>1.56) = 1 - P(z

\\ P(z>1.56) = P(\overline{X}>89.87) = 0.0594

Thus, "The probability that the sample mean would be greater than 89.87 WPM" is about \\ P(z>1.56) = 0.0594.

5 0
3 years ago
A company knows that 30% of Customers who come to the store will check out the merchandise and then order it online because it i
valentinak56 [21]
Let X be a discrete random variable with geometric distribution.
 Let x be the number of tests and p the probability of success in each trial, then the probability distribution is:
 P (X = x) = p * (1-p) ^ (x-1). With x = (1, 2, 3 ... n).
 This function measures the probability P of obtaining the first success at the x attempt.
 We need to know the probability of obtaining the first success at the third trial.
  Where a success is defined as a customer buying online.
 The probability of success in each trial is p = 0.3.
 So:
 P (X = 3) = 0.3 * (1-0.3) ^ (3-1)
 P (X = 3) = 0.147
 The probability of obtaining the first success at the third trial is 14.7%
7 0
3 years ago
22 8(11 + 2r) = 126r + 3
natulia [17]

8(11 + 2r) = 126r + 3​

first open the parenthesis

88 + 16r = 126r + 3

88 - 3 = 126r - 16 r

85 = 110r

divide both-side of the equation by 110

85/110 = r

r= 17/22

7 0
1 year ago
Pls hurry it is 23 points i need help now Match the equation on the left with the correct estimate on the right. Each equation h
azamat
It looks floppy but you said you need this fast so yeah

6 0
3 years ago
Read 2 more answers
Okay someone help me please what is ten times negative three ? ):
mr_godi [17]

Answer:

-30

Step-by-step explanation:

10 x 3 = 30

10 x -3= -30

please mark me brainliest

two negatives makes a positive

two positives markets a negative

and

a positive and a negative makes a negative

5 0
3 years ago
Read 2 more answers
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