To find the average rate of change of given function f(x) on a given interval (a,b):
Find f(b)-f(a), b-a, and then divide your result for f(b)-f(a) by your result for b-a:
f(b) - f(a)
------------
b-a
Here your function is f(x) = x^2 - 2x + 3. Substituting b=5 and a=-2,
f(5) = 5^2 -2(5)+3 =? and f(-2) = (-2)^2 - 2(-2) + 3 = ?
Calculate f(5) - [ f(-2) ]
------------------ using your results, above.
5 - [-2]
Your answer to this, if done correctly, is the "average rate of change of the function f(x) = x^2+2x+3 on the interval [-2,5]."
Answer:
Bet
Step-by-step explanation:
It’s a simple one to write. There are many trios of integers (x,y,z) that satisfy x²+y²=z². These are known as the Pythagorean Triples, like (3,4,5) and (5,12,13). Now, do any trios (x,y,z) satisfy x³+y³=z³? The answer is no, and that’s Fermat’s Last Theorem.
On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?
That turned out to be much harder—as in, no one was able to solve for those integers for 65 years until a supercomputer finally came up with the solution to 42. (For the record: x = -80538738812075974, y = 80435758145817515, and z = 12602123297335631. Obviously.)
9514 1404 393
Answer:
5. x = 160; y = 20
6. h = 125°; g = i = 55°
Step-by-step explanation:
Vertical angles are found on opposite sides of a point where lines cross. Each angle is formed from rays opposite those of the other angle. Vertical angles are congruent.
5. x° and 160° are vertical angles: x° = 160°
y° and 20° are vertical angles: y° = 20°
__
6. h° and 125° are vertical angles: h° = 125°
The angles g° and 125° form a "linear pair" so total 180°.
g° = 180° -125° = 55°
g° and i° are vertical angles: g° = i° = 55°
Answer:
1.25
Step-by-step explanation:
Answer:
1. -18x+6
multiply everything inside with the number outside the bracket
2. -18x-6
same as number one
3. 18x-12
same as number one
4. -18x-6
same as number one
for 5 I can't see it well but it should be similar
you just need to substitute what's outside the bracket to what Is inside the bracket
