Question

In the diagram, ABC is a right - angled triangle.

Answer 1

$\to \rm \sin(30) = \dfrac{AC }{AB}$

$\to \rm \sin(30) = \dfrac{AC }{40}$

$\to \rm \dfrac{1}{2} = \dfrac{AC }{40 \degree}$

$\to \rm \dfrac{40}{2} =AC$

$\to \rm \: AC = 20 m$