Answer:
Rocket B reaches a maximum height that is greater than the maximum height of Rocket A.
Step-by-step explanation:
A graph quickly shows the answer to this question.
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In vertex form, the equation for Rocket A is ...
y = -6(x² -16x +8²) +6(8²)
y = -6(x -8)² +384 . . . . . . . . . maximum height is 384 feet
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The corresponding equation for Rocket B is ...
y = -4(x² -20x +10²) +4(10²)
y = -4(x -10)² +400 . . . . . . . . maximum height is 400 feet
Rocket B reaches a maximum height greater than that of Rocket A.
Answer: y=2x-1
We know that the equation of a line is y = mx + b, where m is the gradient and b is the y-intercept.
First to find the gradient, we use the formula y2-y1/x2-x1.
x1 and y1 being the first set of coordinates (2,3) and x2 and y2 being the second set (4,7)
Now we sub in:
m=7-3/4-2
m=4/2
m=2
This is our gradient and we can put it into the equation: y=2x+b
Now we find the y-intercept (b). Since the y-intercept isn’t shown, we can sub in the coordinates to find it.
y=2x+b
Sub (2,3)
3=2(2)+b
3=4+b
-1=b
Sub (4,7)
7=2(4)+b
7=8+b
-1=b
Subbing in both coordinates gives us -1 as the y-intercept, so the finished equation is: y=2x-1
<span>Traveled Downstream a distance of 33 Mi and then came right back. If the speed of the current was 12 mph and the total trip took 3 hours and 40 minutes.
Let S = boat speed in still water then (s + 12) = downstream speed (s -12) = upstream speed
Given Time = 3 hours 40 minutes = 220 minutes = (220/60) h = (11/3) h Time = Distance/Speed
33/(s +12) + 33/(s-12) = 11/3 3{33(s-12) + 33(s +12)} = 11(s+12) (s -12) 99(s -12 + s + 12) = 11(</span> s^{2} + 12 s -12 s -144) 99(2 s) = 11(s^{2} -144) 198 s/11 = (s^{2} -144) 18 s = (s^{2} -144) (s^{2} - 18 s - 144) = 0 s^{2} - 24 s + 6 s -144 =0 s(s- 24) + 6(s -24) =0 (s -24) (s + 6) = 0 s -24 = 0, s + 6 =0 s = 24, s = -6 Answer) s = 24 mph is the average speed of the boat relative to the water.
Answer: if you divide 15.55 by 5 the unit price is $3.11