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Studentka2010 [4]
4 years ago
15

What is 4.51 rounded to the nearest whole number

Mathematics
1 answer:
iren2701 [21]4 years ago
6 0
Answer:

4.51 rounded to the nearest whole number is 5.
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Solve for "H"<br> Due by 2:00<br> Plz Help
Reptile [31]

Answer:

H = 12

Step-by-step explanation:

Add the angles, 54 + 63 + 5h + 3 = 180

simplify into 120 + 5h = 180

5h = 60

h = 12

8 0
3 years ago
Help plzzzzzz! Sandy works at a clothing store. She makes $9 per hour plus earns 10% commission on her sales. She worked 72 hour
Mamont248 [21]

Answer:

Step-by-step explanation:

Payment per hour is $8

commission is 15%

Total number of hours worked for 2 weeks is 73 hours

Total sales=$2095

commission earned for 2 weeks:

15/100×2095

=$314.25

Total amount earned in 73 hours:

73×8=$584

Total amount earned in commission and wages:

584+314.25

=$898.25

4 0
3 years ago
Choose 2 trapezoids and find the area using proper format
masha68 [24]

Answer:

Area of green trapezoid would be:

(length of two parallel sides × h) ÷ 2

( 5cm x 2cm) ÷ 2

= 5 square centimetres

Area of the orange trapezoid would be:

(length of two parallel sides x h) ÷ 2

(10.5 cm × 3) ÷ 2

( 31. 5) ÷ 2

(15. 75 square centimetres

NOTE: h represents height

8 0
4 years ago
Benjamin decides to treat himself to breakfast at his favorite restaurant. He orders chocolate milk that costs \$3.25$3.25dollar
MaRussiya [10]

Answer:

4 stacks of packages

4 * 4 = 16 pieces of pancake

Step-by-step explanation:

Maximum amount to spend ≤ $30

Milk chocolate = $3.25

Pancakes per stack = 5.50 (sold in stacks of 4)

Let number of stacks = s

In equality terms :

3.25 + 5.50s ≤ 30

5.50s ≤ 30 - 3.25

5.50s ≤ 26.75

s ≤ 26.75 / 5.50

s ≤ 4.86

Hence, 4 stacks of pancakes can be purchased

8 0
3 years ago
Coefficiants of (2x+y)^4​
sattari [20]

By the binomial theorem,

(2x+y)^4=\displaystyle\sum_{k=0}^4\binom 4k(2x)^{4-k}y^k=\sum_{k=0}^4\binom 4k2^{4-k}x^{4-k}y^k

where

\dbinom nk=\dfrac{n!}{k!(n-k)!}

Then the coefficients of the x^{4-k}y^k terms in the expansion are, in order from k=0 to k=4,

\dbinom 402^{4-0}=1\cdot2^4=16

\dbinom412^{4-1}=4\cdot2^3=32

\dbinom422^{4-2}=6\cdot2^2=24

\dbinom432^{4-3}=4\cdot2^1=8

\dbinom442^{4-4}=1\cdot2^0=1

3 0
3 years ago
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