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vladimir1956 [14]

3 years ago

6

The actual length of Wall C is 4 m. To represent Wall C, Noah draws a segment 16 cm long. What scale is he using?

1 answer:

hjlf3 years ago

4 0

Answer:

$\frac{1m}{4cm}$

Step-by-step explanation:

First write the problem out as a fraction.

$\frac{4}{16}$

Next see if there is a GCF

4:1,2,4

16:1,2,4,8,16

Finally divide the numerator and denomenator by the GCF

$\frac{4}{16} /4=\frac{1}{4}$

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A fluid moves through a tube of length 1 meter and radius r=0.006±0.00025 meters under a pressure p=4⋅105±2000 pascals, at a rat

iris [78.8K]

Answer:

Maximum error for viscosity is 17.14%

Step-by-step explanation:

We know that everything is changing with respect to the time, "r" is changing with respect to the time, and also "p" just "v" will not change with the time according to the information given, so we can find the implicit derivative with respect to the time, and since

$n = (\frac{\pi}{8}) (\frac{pr^4}{v})\\$

The implicit derivative with respect to the time would be

$\frac{dn}{dt} = \frac{\pi}{8} ( \frac{r^4}{v} \frac{dp}{dt} + \frac{4pr^3}{v}\frac{dr}{dt} )$

If we multiply everything by dt we get

$dn = \frac{\pi}{8} ( \frac{r^4}{v} dp + \frac{4pr^3}{v} dr})$

Remember that the error is given by $\frac{dn}{n}$ therefore doing some algebra we get that

$\frac{dn}{n} = 4 \frac{dr}{r} + \frac{dp}{p}$

Since, r = 0.006 , dr = 0.00025 , p = 4*105 , dp = 2000 we get that

$\frac{dn}{n} = 0.1714$

Which means that the maximum error for viscosity is 17.14%.

5 0

3 years ago

How many 0.4 L glasses can be filled from<br> a 4.75 L jug of juice?

nata0808 [166]

Answer:

11

Step-by-step explanation:

8 0

3 years ago

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What is the range of the function graphed below?

vovangra [49]

The answer is A. -∞ < y < 2

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3 years ago

35 equals:<br> A. 53<br> B._35<br> D.243<br> E. 81

Zepler [3.9K]

If you meant to say 3^5 or $3^5$ , then,

$3^5 = 3*3*3*3*3 = 243$ (there are five copies of '3' multiplied)

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3 years ago

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There is a light post that is 9 feet tall that casts a shadow that is 6 feet long. At the same time, there is a tree that casts

Salsk061 [2.6K]

Answer:

The height of the tree is 21 ft

Step-by-step explanation:

we know that

A light post that is 9 feet tall that casts a shadow that is 6 feet long

so

by proportion

Find out the the height of the tree if a tree that casts a shadow that is 14 feet long

Let

x ----> the height of the tree

$\frac{9}{6}=\frac{x}{14}\\\\x=9*14/6\\\\x=21\ ft$

therefore

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6 0

3 years ago