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Hunter-Best [27]
3 years ago
10

Graph the solution on a number line -6x+3>-39

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
5 0

Step-by-step explanation:

-6x+3>-39\qquad\text{subtract 3 from both sides}\\\\-6x+3-3>-39-3\\\\-6x>-42\qquad\text{change the all signs}\\\\6x

-\text{op}\text{en circle}-\circ\\\leq,\ \geq-\text{closed circle}-\bullet\\\\,\ \geq-\text{draw the line to the right}

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The cost of a pizza at the pizza palace depends on the size of the pizza and the number of toppings. For a large pizza, the cost
NeX [460]

Answer:

The 2 represents that each toppings costs $2.

5 0
3 years ago
What is the anser to the equation 2^{2x+2} = 2^{3x}
Marianna [84]

Answer: C) x = 2

2^{2x + 2} = 2^{3x}

Since both terms (above) have the same base, set the exponents to be equal:

2x + 2 = 3x (Rearrange to solve for x)

x = 2

∴ x = 2

8 0
2 years ago
Please help me i'll mark brainliest.
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3 years ago
Read 2 more answers
Or the past 100 years, the average high temperature on october 1 is 78° with a standard deviation of 5°. what is the probability
valina [46]

Answer:

The probability is 0.683

Step-by-step explanation:

To calculate this, we shall be needing to calculate the z-scores of both temperatures

mathematically;

z-score = (x-mean)/SD

From the question mean = 78 and SD = 5

For 73

z-score = (73-78)/5 = -5/5 = -1

For 83

z-score = (83-78)/5 = 5/5 = 1

So the probability we want to calculate is within the following range of z-scores;

P(-1 <z <1 )

Mathematically, this is same as ;

P(z<1) - P(z<-1)

Using the normal distribution table;

P(-1<z<1) = 0.68269 which is approximately 0.683

3 0
3 years ago
3. At noon Lan is in his blue mini-van 300 km north of Makenna in her Bugatti. Lan heads south
LiRa [457]

Answer:

The rate at which the distance between them is changing at 2:00 p.m. is approximately 1.92 km/h

Step-by-step explanation:

At noon the location of Lan = 300 km north of Makenna

Lan's direction = South

Lan's speed = 60 km/h

Makenna's direction and speed = West at 75 km/h

The distance  Lan has traveled at 2:00 PM = 2 h × 60 km/h = 120 km

The distance north between Lan and Makenna at 2:00 p.m = 300 km - 120 km = 180 km

The distance West Makenna has traveled at 2:00 p.m. = 2 h × 75 km/h = 150 km

Let 's' represent the distance between them, let 'y' represent the Lan's position north of Makenna at 2:00 p.m., and let 'x' represent Makenna's position west from Lan at 2:00 p.m.

By Pythagoras' theorem, we have;

s² = x² + y²

The distance between them at 2:00 p.m. s = √(180² + 150²) = 30·√61

ds²/dt = dx²/dt + dy²/dt

2·s·ds/dt = 2·x·dx/dt + 2·y·dy/dt

2×30·√61 × ds/dt = 2×150×75 + 2×180×(-60) = 900

ds/dt = 900/(2×30·√61) ≈ 1.92

The rate at which the distance between them is changing at 2:00 p.m. ds/dt ≈ 1.92 km/h

5 0
3 years ago
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