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Korolek [52]
3 years ago
10

|60| ___ |-60| = < >

Mathematics
1 answer:
Klio2033 [76]3 years ago
6 0

they are equal to each other


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Cual es el resultado?/ who is the answer? <br> -m+4-(-m)=
Debora [2.8K]

Answer:

-m+4-(-m) = -m+4+m \\                  = 4

8 0
3 years ago
In a lab, a scientist is growing bacteria for a study. The scientist begins with a bacteria
Diano4ka-milaya [45]

Answer:

The answer is below

Step-by-step explanation:

The growth of the bacteria is in the form of an exponential growth. It is given by the formula:

P(t)=ae^{rt}\\\\where\ t\ is\  the\ number\ of \ hours, P(t)\ is\ the \ population\ at\ t\ hours\\\and\ a=population\ at\ start

At 2 hours, the population is 62 cells, hence:

P(2)=ae^{2r}\\\\62=ae^{2r}\ \ .\ \ .\ \ .\ (1)

After another 2 hours (4 hours), the population is 1 million:

P(4)=ae^{4r}\\\\1000000=ae^{4r}\ \ .\ \ .\ \ .\ (2)\\\\Divide \ equation\ 2\ by\ equation\ 1:\\\\\frac{1000000}{62}=\frac{ae^{4r}}{ae^{2r}} \\\\16129=e^{2r}\\\\ln(e^{2r})=ln(16129)\\\\2r=9.688\\\\r=4.844

Put r = 4.844 in equation 1

62=ae^{2*4.844}\\\\62=16129a\\\\a=0.003844

P(t)=0.003844e^{4.844t}\\\\at \ start,t=0\\\\P(0)=0.003844

4 0
3 years ago
Find the total area of the net below. 5 points each please help. Thanks! and have good day!
Vinil7 [7]

Answer:

Sorry the screenshot is black but i would like to help if you can repost, it?

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the solution to the system of equations?
Alisiya [41]
Solve systems of equations by graphing. A system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. The solution of such a system is the ordered pair that is a solution to both equations. To solve a system of linear equations graphically we graph both equations in the same coordinate system.
5 0
3 years ago
Read 2 more answers
Find u and v only please:
tekilochka [14]

Every two triangles are similar. Therefore the sides of triangles are in proportion.

We have the equations:

1.

\dfrac{3}{5}=\dfrac{3+x}{20}    <em>cross multiply</em>

5(3+x)=(3)(20)      <em>divide both sides by 5</em>

3+x=(3)(4)

3+x=12      <em>subtract 3 from both sides</em>

\boxed{x=9}

--------------------------------------

2.

\dfrac{3}{4}=\dfrac{9}{y}      <em>cross multiply</em>

3y=(4)(9)

3y=36      <em>divide both sides by 3</em>

\boxed{y=12}

------------------------------------------

3.

\dfrac{3}{5}=\dfrac{3+9+u}{60}

\dfrac{3}{5}=\dfrac{12+u}{60}    <em>cross multiply</em>

5(12+u)=(3)(60)      <em>divide both sides by 5</em>

12+u=(3)(12)

12+u=36      <em>subtract 12 from both sides</em>

\boxed{u=24}

----------------------------------------------

4.

\dfrac{3}{4}=\dfrac{24}{v}              <em>cross multiply</em>

3v=(4)(24)

3v=96      <em>divide both sides by 3</em>

\boxed{v=32}

3 0
3 years ago
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