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lbvjy [14]
3 years ago
14

4x2 + 2x = 12 What's the answer Nd solve it

Mathematics
2 answers:
baherus [9]3 years ago
8 0

Answer:

=3/2

=−2

2Step-by-step explanation:

anygoal [31]3 years ago
4 0

Answer:

The answer is x=2

Step-by-step explanation:

First, we need to use the order of operations, which states that multiplication happens first. This gives us 8+2x=12. Now we need to get the exponent by itself. To do this, subtract 8 from both sides. This gives us 2x=4. Now, divide both sides by 2. You get x=2.

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Which number has the greatest absolute value?<br> A) 15 <br> B) 5 <br> C) 0 <br> D) −25
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Simplify: |3−8|−(12÷3+1)2
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Answer:

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4 years ago
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A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
8 0
3 years ago
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