The ticket price of the item after applying coupon B first and then coupon A is $65.45
Coupons reduce the ticket price of an item.
<u><em>Ticket price</em></u><u><em> after </em></u><u><em>coupon B i</em></u><u><em>s applied </em></u>
An item costs $80. After applying the coupon B which gives, $3 off the price, the cost of the item reduces to $77 ($80 - $3).
The ticket price of the item after coupon B is applied is $77
<em><u>Ticket price </u></em><em><u>after c</u></em><em><u>oupon A </u></em><em><u>is applied </u></em>
The item costs $77 when coupon B is applied. If the discount is 15% off on coupon A, it means that the item costs 85%( 100 - 15%) of its initial price.
Ticket Price of the item = percentage price x price of the item after the first coupon B was applied
85% x $77
0.85 x $77 = $65.45
A similar question was solved here: brainly.com/question/17413216?referrer=searchResults
9514 1404 393
Answer:
-4
Step-by-step explanation:
The points at the ends of the interval are ...
(3, f(3)) = (3, 8)
(6, f(6)) = (6, -4)
The slope is given by the slope formula:
m = (y2 -y1)/(x2 -x1)
m = (-4 -8)/(6 -3) = -12/3 = -4
The average rate of change is -4.
Let "a" and "s" represent the costs of advance and same-day tickets, respectively. Your problem statement gives you two relations.
.. a + s = 35 . . . . . the combined cost of one of each is 35
.. 15a +40s = 900 . . total paid for this combination of tickets was 900
There are many ways to solve these equations. You've probably been introduced to "substitution" and "elimination" (or "addition"). Using substitution for "a", we have
.. a = 35 -s
.. 15(35 -s) +40s = 900 . . substitute for "a"
.. 25s +525 = 900 . . . . . . . simplify
.. 25s = 375 . . . . . . . . . . . .subtract 525
.. s = 15 . . . . . . . . . . . . . . .divide by 25
Then
.. a = 35 -15 = 20
The price of an advance ticket was 20.
The price of a same-day ticket was 15.
Answer:
r=56
Step-by-step explanation:
252= r * 4.5
r * 4.5 = 252
r * 4.5 * 10 = 252 * 10
45r = 2520
r = 56
