The maximum value of the objective function is 26 and the minimum is -10
<h3>How to determine the maximum and the minimum values?</h3>
The objective function is given as:
z=−3x+5y
The constraints are
x+y≥−2
3x−y≤2
x−y≥−4
Start by plotting the constraints on a graph (see attachment)
From the attached graph, the vertices of the feasible region are
(3, 7), (0, -2), (-3, 1)
Substitute these values in the objective function
So, we have
z= −3 * 3 + 5 * 7 = 26
z= −3 * 0 + 5 * -2 = -10
z= −3 * -3 + 5 * 1 =14
Using the above values, we have:
The maximum value of the objective function is 26 and the minimum is -10
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Answer:2
Step-by-step explanation:
Answer:
x=12
Step-by-step explanation:
For the given situation , a quantity x is added to 
gives 15.
We can set up equation as
Multiply each term by 4 on both sides to get rid the denominator.
It gives,
4 x+x=60
Now, combine like terms
5 x=60
Divide both sides by 5
x=12.
Answer:
Boys: 75%
Girls: 25%
Step-by-step explanation:
Total: 28 Students: 100%
7 Girls in clas
28(total)-7 (girls)= 21 Boys in class
__________________
If we divide the amount boys OR girls ( depending on which gender) after the toal and move the decimal to the right twice after dividing) we will get our answer.
Formula:
(Amount of Boy or girls) = x
X/28
So since we are trying to get the percentages of boys, we will replace X with the amount of boys
21/28 = .75 ( then move the decimal to the right TWICE) = 75
Then you should get your percentages: 75% Also if your lookings for girls percentages, you basically subtract 75 ( boys percentages) with the total percentages ( 100) then you should get your answer for the girls: 25%
.162 kilograms?
How I got my answer:
1.35÷500=.0027
.0027×60=.162
