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irakobra [83]
3 years ago
8

Discount tickets to a basketball tournament sell for $4.00 each. Sam spent $60.00 on discount tickets, $37.50 less than if he ha

d bought the tickets at the regular price. What was the regular price?
Mathematics
1 answer:
nignag [31]3 years ago
5 0

Answer: the regular price is $6.5 each.

Step-by-step explanation:

Let x represent the regular price of a ticket to a basketball tournament.

Discount tickets to a basketball tournament sell for $4.00 each. Sam spent $60.00 on discount tickets. This means that the number of tickets that Sam bought is

60/4 = 15 tickets

The cost of 15 tickets at the regular price is 15x

Since the amount he paid is $37.5 lesser than what he would have paid if he bought the tickets at the regular price, then

15x = 60 + 37.5 = 97.5

x = 97.5/15

x = 6.5

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F) Two numbers are in the ratio 5:4. If they differ by 12, what are the numbers?
Iteru [2.4K]

Answer:

First number = 60 and another number = 48

Step-by-step explanation:

Let two numbers are 5x and 4x.

The two number are differ by 12. We need to find the numbers.

ATQ,

5x-4x = 12

x = 12

Now first number = 5x

= 5(12)

= 60

Other number = 4x

= 4(12)

= 48

Hence, the numbers are 60 and 48.

8 0
3 years ago
Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3 5 , KE = 8, LM KN = 3 5 Find: KM, LM, KN, Area of KLMN
prisoha [69]
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the 
KM² = KE² + ME²KM² = 8² + (3√5)²       = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N  Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the  formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM)          = 1/2 * 3√5 * (40 + 24)         = 1/2 * 3√5 * 64         = 3 x 2.23 * 32         = 214.66 units²
7 0
3 years ago
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nalin [4]

Answer:

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I think the answer is x^2+6
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