A soft drink machine outputs a mean of 27 ounces per cup. The machine's output is normally distributed with a standard deviation
 of 3 ounces. What is the probability of filling a cup between 21 and 28 ounces? Round your answer to four decimal places.
       
      
                
     
    
    
    
    
    1 answer:
            
              
              
                
                
Answer:  0.6065
Step-by-step explanation:
Given : The machine's output is normally distributed with


Let x be the random variable that represents the output of machine .
z-score : 
For x= 21 ounces
 
For x= 28 ounces
 
Using the standard normal distribution table , we have
The p-value : 

Hence, the probability of filling a cup between 21 and 28 ounces=  0.6065
 
                                
             
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