Answer:
Step-by-step explanation:
<u>Given recursive formula</u>
- a₁ = 0
- aₙ = 2(aₙ₋₁)² - 1, for n>1
<u>The first 5 terms are:</u>
- a₁ = 0
- a₂ = 2(0)² - 1 = 0 - 1 = -1
- a₃ = 2(-1)² - 1 = 2 - 1 = 1
- a₄ = 2(1)² - 1 = 2 - 1 = 1
- a₅ = 2(1)² - 1 = 2 - 1 = 1
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 2: Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 3: Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).
Step 4: Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7), 9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.
Step 5: Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
The sequence is geometric, so
![a_n = r a_{n-1}](https://tex.z-dn.net/?f=a_n%20%3D%20r%20a_%7Bn-1%7D)
for some constant r. From this rule, it follows that
![a_3 = r a_2 \implies 20 = 2r \implies r = 10](https://tex.z-dn.net/?f=a_3%20%3D%20r%20a_2%20%5Cimplies%2020%20%3D%202r%20%5Cimplies%20r%20%3D%2010)
and we can determine the first term to be
![a_2 = r a_1 \implies 2 = 10 a_1 \implies a_1 = \dfrac15](https://tex.z-dn.net/?f=a_2%20%3D%20r%20a_1%20%5Cimplies%202%20%3D%2010%20a_1%20%5Cimplies%20a_1%20%3D%20%5Cdfrac15)
Now, by substitution we have
![a_n = r a_{n-1} = r^2 a_{n-2} = r^3 a_{n-3} = \cdots](https://tex.z-dn.net/?f=a_n%20%3D%20r%20a_%7Bn-1%7D%20%3D%20r%5E2%20a_%7Bn-2%7D%20%3D%20r%5E3%20a_%7Bn-3%7D%20%3D%20%5Ccdots)
and so on down to (D)
![a_n = r^{n-1} a_1 = 10^{n-1} \cdot \dfrac15](https://tex.z-dn.net/?f=a_n%20%3D%20r%5E%7Bn-1%7D%20a_1%20%3D%2010%5E%7Bn-1%7D%20%5Ccdot%20%5Cdfrac15)
(notice how the exponent on r and the subscript on a add up to n)
Answer:
B
Step-by-step explanation:
Complementary angles are when two angles add up to 90 degrees.
The answer is 14 you just have to substitute x with the given number and finish the equation