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2 years ago

How can you multiply (2)(-3)(-2)

Mathematics

2 answers:

Eduardwww [97]2 years ago

5 0

Answer:

-12

Step-by-step explanation:

So first 2 * -3 * -2

-3 * -2 = 6 because the negatives cancel themselves out;

2 * -6 = -12

Anestetic [448]2 years ago

3 0

2•-3= -6 | -6•-2= 12

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GenaCL600 [577]

Answer:

Yumiko should multiply the other equation by 3.

If she adds the two equations she would be left with the variable 'x'.

Step-by-step explanation:

Given the two equations are as follows:

$2x - 3y = 12 \hspace{5mm} \hdots (1)$

$5x + 6y = 18 \hspace{5mm} \hdots (2)$

It is given that she multiplies the first equation by 6. Therefore, (1) becomes

$12x - 18y = 72 \hspace{15mm} \hdots (a)$

Now, note that the sign of the variable 'y' is negative. So, if we make the co-effecient of 'y' equal in both the cases, add them it would result in the elimination of the variable 'y'.

The co-effecient of y in Equation (2) is 6. To make it 18 like it is in Equation (1), we multiply throughout by 3.

Therefore, Equation (2) becomes:

$15x + 18y = 54 \hspace{5mm} \hdots (b)$

Now, we add Equation (a) and Equation (b).

$\implies 12x - 18y + 15x + 18y = 72 + 54$

$\implies 27x = 126$

Factor: 3

Equation: 27x = 126

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Answer:

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2 years ago

How can you multiply (2)(-3)(-2)​

How can you multiply (2)(-3)(-2)