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3 years ago

Who could help me in mathematics

Mathematics

1 answer:

Vikki [24]3 years ago

7 0

Rhombus no right angles 2 pairs of parallel sides

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How many consecutive zeros are there at the end of the expansion of 1,000 factorial?

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249 Zeros in the expansion of 1,000

3 0

3 years ago

Read 2 more answers

Who ever answers this first gets brainly

Ronch [10]

Answer:

d. 188.4 in

Step-by-step explanation:

i might be wrong so sorry in advance.

7 0

2 years ago

Pls owrk out the missing angle

Alik [6]

Answer:

125

Step-by-step explanation:

A full circle is 360°

80+85+70=235

360-235=125

4 0

3 years ago

I need help finding the area

aniked [119]

<h3>Given :</h3>

Base of triangle = 7 yd
Height of triangle = 10 yd

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Area of triangle

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We know:-

When base and height of triangle is given we use this formula:

$\bigstar \boxed{ \rm Area \: of \: triangle = \frac{base \times height}{2} }$

$\\ \\$

So:-

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{base \times height}{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 10}{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times2 }{2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times\cancel2 }{\cancel2} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle = \dfrac{7 \times 5 \times1 }{1} \\$

$\\ \\$

$\dashrightarrow \sf \: Area \: of \: triangle =7 \times 5$

$\\ \\$

$\dashrightarrow \bf \: Area \: of \: triangle =35 {yd}^{2} \\$

$\\ \\$

$\therefore \underline{\textsf{ \textbf {\: Area \: of \: triangle = \red{35}}} { \red{\bf{yd} }^{ \red2} }}$

$\\ \\$

$\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}$ ]

7 0

2 years ago

30 pts ! The height of the Ferris wheel in feet can be represented by the function 50 cos (π/15(x-10))+52 with time in x seconds

Dahasolnce [82]

h = 50 cos ( pie(x - 10 )/15 ) + 52

80 = 50 cos ( pie( x - 10 )/15 ) + 52

80 - 52 = 50 cos ( pie( x - 10 )/15 )

28 = 50 cos ( pie( x - 10 )/15 )

cos ( pie( x - 10 )/15 ) = 28/50

cos ( pie( x - 10 )/15 ) = 56/100

cos ( pie( x - 10 )/15 ) = cos ( 56 )

cos ( pie( x - 10 )/15 ) = cos ( 0.3111 pie )

Thus ;

pie( x - 10 )/15 = 0.3111 pie

( x - 10 )/15 = 0.3111

x - 10 = 15 × 0.3111

x - 10 = 4.6665

x = 10 + 4.6665

x = 14.6665 [ approximately ]

Thus the correct answer is exactly what u chose goodjob .....

7 0

3 years ago