Evaluate the expression 72/x2-2 for x=3

A bulletin board can be covered completely by 30 square pieces of paper without any gaps or overlaps. If each piece of paper has

9966 [12]

Can you help me please I need help with a couple of questions

7 0

3 years ago

Evaluate the quantity 3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two.

svetoff [14.1K]

16/27 is the value of quantity.

What is a linear equation in math?

A linear equation only has one or two variables. No variable in a linear equation is raised to a power greater than 1 or used as the denominator of a fraction.
When you find pairs of values that make a linear equation true and plot those pairs on a coordinate grid, all of the points lie on the same line.
There are three major forms of linear equations: point-slope form, standard form, and slope-intercept form. We review all three in this article.
Some of the examples of linear equations are 2x – 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, x + y = 2, 3x – y + z = 3.

$\frac{3^{2} * 3^{-5} }{4^{2} } = \frac{3^{-3} }{4^{-2} }$

$\frac{1}{3^{3} }$ ÷ $\frac{1}{4^{2} }$

$\frac{1}{27} * 16 = \frac{16}{27}$

Learn more about linear equation

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6 0

1 year ago

The distribution of a sample of the outside diameters of PVC pipes approximates a normal distribution. The mean is 14.0 inches,

lakkis [162]

Answer:

A. 13.9 and 14.1 inches

See explanation below.

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the outside diameters of a population, and for this case we know the distribution for X is given by:

$X \sim N(14,0.1)$

Where $\mu=14$ and $\sigma=0.1$

If we want the middle 68% of the data we need to have on the tails 16% on each one

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.84$ (a)

$P(X$ (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.16 of the area on the left and 0.84 of the area on the right it's z=-0.994. On this case P(Z<-0.994)=0.16 and P(z>-0.994)=0.84

If we use condition (b) from previous we have this:

$P(X$