Ask question

Ask question

All categories

2 years ago

10

(PLEASE HELP) To feed 7 horses for 4 days, Mark needs 420 kg of grass. How many kilograms of grass does Mark need to feed 9 hors

es for 6 days?

2 answers:

DerKrebs [107]2 years ago

7 0

Answer:

810kg is the answer

Step-by-step explanation:

Hope this helps:)

Vlada [557]2 years ago

6 0

420 divided by 4 is 105 so each day 7 horses eat 105 kg of grass,
105 divided by 7 = 15 so each horse intakes 15 kg of grass per day

9x15=135
135x6 =810

You might be interested in

Shelley drove a car for 476 miles using 17 gallons of gas. At that rate, how many miles can she travel by car using 30 gallons o

lana [24]

At this rate she can travel 840 miles using 30 gallons of gas.

7 0

3 years ago

Can anybody help plzz?? 65 points

Yakvenalex [24]

Answer:

$\frac{dy}{dx} =\frac{-8}{x^2} +2$

$\frac{d^2y}{dx^2} =\frac{16}{x^3}$

Stationary Points: See below.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Equality Properties

<u>Calculus</u>

Derivative Notation dy/dx

Derivative of a Constant equals 0.

Stationary Points are where the derivative is equal to 0.

1st Derivative Test - Tells us if the function f(x) has relative max or mins. Critical Numbers occur when f'(x) = 0 or f'(x) = undef
2nd Derivative Test - Tells us the function f(x)'s concavity behavior. Possible Points of Inflection/Points of Inflection occur when f"(x) = 0 or f"(x) = undef

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

<u>Step 1: Define</u>

$f(x)=\frac{8}{x} +2x$

<u>Step 2: Find 1st Derivative (dy/dx)</u>

Quotient Rule [Basic Power]: $f'(x)=\frac{0(x)-1(8)}{x^2} +2x$
Simplify: $f'(x)=\frac{-8}{x^2} +2x$
Basic Power Rule: $f'(x)=\frac{-8}{x^2} +1 \cdot 2x^{1-1}$
Simplify: $f'(x)=\frac{-8}{x^2} +2$

<u>Step 3: 1st Derivative Test</u>

Set 1st Derivative equal to 0: $0=\frac{-8}{x^2} +2$
Subtract 2 on both sides: $-2=\frac{-8}{x^2}$
Multiply x² on both sides: $-2x^2=-8$
Divide -2 on both sides: $x^2=4$
Square root both sides: $x= \pm 2$

Our Critical Points (stationary points for rel max/min) are -2 and 2.

<u>Step 4: Find 2nd Derivative (d²y/dx²)</u>

Define: $f'(x)=\frac{-8}{x^2} +2$
Quotient Rule [Basic Power]: $f''(x)=\frac{0(x^2)-2x(-8)}{(x^2)^2} +2$
Simplify: $f''(x)=\frac{16}{x^3} +2$
Basic Power Rule: $f''(x)=\frac{16}{x^3}$

<u>Step 5: 2nd Derivative Test</u>

Set 2nd Derivative equal to 0: $0=\frac{16}{x^3}$
Solve for <em>x</em>: $x = 0$

Our Possible Point of Inflection (stationary points for concavity) is 0.

<u>Step 6: Find coordinates</u>

<em>Plug in the C.N and P.P.I into f(x) to find coordinate points.</em>

x = -2

Substitute: $f(-2)=\frac{8}{-2} +2(-2)$
Divide/Multiply: $f(-2)=-4-4$
Subtract: $f(-2)=-8$

x = 2

Substitute: $f(2)=\frac{8}{2} +2(2)$
Divide/Multiply: $f(2)=4 +4$
Add: $f(2)=8$

x = 0

Substitute: $f(0)=\frac{8}{0} +2(0)$
Evaluate: $f(0)=\text{unde} \text{fined}$

<u>Step 7: Identify Behavior</u>

<em>See Attachment.</em>

Point (-2, -8) is a relative max because f'(x) changes signs from + to -.

Point (2, 8) is a relative min because f'(x) changes signs from - to +.

When x = 0, there is a concavity change because f"(x) changes signs from - to +.

3 0

3 years ago

the vertex of this parabola is at (-3,-1). when the y-value is 0, the x-value is 4. what it the coefficient of the squared term

Len [333]

<span>1/49 = a
have a great day.

</span>

3 0

4 years ago

Read 2 more answers

Plz plz plz this is due today and I really need help

nekit [7.7K]

Answer:

The y-intercept is (0, 34).

I used Demos graphing calculator and included an image of what values I put in.

6 0

3 years ago

A rental moving truck can haul a maximum of 7,500 pounds. Dejuan has boxes that weigh 40 pounds and boxes that weigh 75 pounds.

Lelechka [254]

Answer:

One hundred and fifty 40 pounds boxes and twenty 75 pounds boxes

Step-by-step explaination:

The maximum amount he can haul in one load is 7500 pounds

150 × 40 pounds boxes = 6000 pounds

20 × 75 pounds boxes = 1500 pounds

6000 pounds + 1500 pounds = 7500 pounds

8 0

3 years ago