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SOVA2 [1]
3 years ago
13

I need an answer for each instance!!! Each a, b, and c is a different mini problem.

Mathematics
1 answer:
user100 [1]3 years ago
7 0
The answer would be c

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Combinations


nCr
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nCr=\frac{n!}{r!(n-r)!}
remember than n! means n times all numbers before like
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9 stations, how many ways are there to chose 6 of them
9C6=\frac{9!}{6!(9-6)!}=
\frac{9!}{6!(3)!}=
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\frac{9*8*7}{3*2*1}=
\frac{3*4*7}{1}=
84

84 ways



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3 years ago
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Podrias explicar lo que estas tratando de buscar? tu pregunta no se entiende
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7 0
3 years ago
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