3 years ago

Please help 25v^2-20vx+4x^2

1 answer:

7 0

$25v^2-20vx+4x^2 \\ \\ (5v)^2 - 2(5v)(2x) + (2x)^2 \\ \\ (5v - 2x)^2 \\ \\$

The final result is: (5v - 2x)<span>² </span>

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<u>Step-by-step explanation:</u>

$y = \frac{1}{x^{3}}$

Inverse is when you swap the x's and y's and then solve for "y":

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zhannawk [14.2K]

Lets say the number is ab. Its value is 10a + b

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