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Arada [10]
4 years ago
14

Sally did some counting look at her work explain why you think sally counted this way 177,178,179,180,190,200,220,211,212,213,21

4
Mathematics
1 answer:
dimulka [17.4K]4 years ago
8 0
<span>The first and last four numbers each have a difference of one between them. The fifth number has a difference of 10 between it and the previous number. The middle number has a difference of 20 between itself and the two numbers that surround it. Counting in this way could have been a result of a lot of things to count, and spot checking along the way (when the numbers have a difference of 1).</span>
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Rewrite the following quadratic fiction in vertex form. Then, determine if it has a maximum or minimum and say what that value i
hram777 [196]
First subtract the constant to the other side to simplify it for now
y-5=-x^2+6x
Then pull out a common factor so the coefficient is x^2
y-5=-1(x^2-6x)
Next you take 1/2 of the b value (-6) and square it to find your c value
[1/2(-6)]^2=9
After that plug 9 into your equation as your c value
y-5=-1(x^2-6x+9)
Adding the C-value (9) causes the equations to become unbalanced so you need to balance them back out by minus 9 to the other side
y-14=-1(x^2-6x+9)
Now you want to simplify the equation on the right side.
y-14=-1(x-3)^2
Finally you want to add the constant back to the right side.
y=-1(x-3)^2+14 <——— vertex form

maximum=(3,14)
5 0
4 years ago
Write each complex number in rectangular form.
hram777 [196]
Hello,

A)
cos 135°=- cos 45°=-√2/2
sin 135°=sin45°=√2/2
2(cos 135°+i sin 135°)=-√2 + i*√2

B)
cos 120°=-cos 30°=-√3 /2
sin 120°=sin 30°=1/2

3(cos 120° + i sin 120)=-3/2*√3 +i*3/2

C)
cos (5π/4)=-cos (π/4)=-√2 /2
sin (5π/4)= -sin(π/4)=-√2 /2
5(cos (5π/4)+i sin (5π/4))=-5/2*√2 +i *5/2*√2

D)
cos(5π/3)=cos(π/3)=√3 /2
sin (5π/3)=-sin(π/3)=-1/2

4(cos(5pi/3)+i sin (5pi/3))
=2√3- 2*i


4 0
3 years ago
What is -7+4m+10=15-2m=
Inessa [10]

Answer:

m=2

Step-by-step explanation:

Add the numbers

-7+4m+10=15-2m

3+4m=15-2m

Rearrange terms

3+4m=15-2m

4m+3=15-2m

Rearrange terms

4m+3=15-2m

4m+3=-2m+15

Subtract 3 from both sides of the equation

4m+3=-2m+15

4m+3-3=-2m+15-3

Simplify

4m=-2m+12

Add 2m to both sides of the equation

4m=-2m+12

4m+2m=-2m+12+2m

Simplify

6m=12

Divide both sides of the equation by the same term

6m = 12

6m/6 = 12/6

Simplify

m = 2

5 0
3 years ago
Suppose you write a sum of numbers as a product of their GCF and another sum. What is the GCF of the numbers in the other sum? C
vivado [14]

Answer:

1

Step-by-step explanation:

7 0
3 years ago
PLEASEEE I CAN'T DO ITT
MAXImum [283]

Answer:

answer is cm² ok

Step-by-step explanation:

because it is saying area ,in area we have to put cm2

7 0
2 years ago
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