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MA_775_DIABLO [31]
3 years ago
15

If 10 is reduced by 4 times what will be the answer?? I'm bit confused.....help me out....

Mathematics
1 answer:
babunello [35]3 years ago
3 0
I don't really understand the question
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The Cheer Club is making a banner for your school using the design shown. The area of the yellow portion is 1 ft2. The expressio
olga nikolaevna [1]

Answer:

Blue = \frac{8}{9}

Step-by-step explanation:

Given

Yellow = 1ft^2

Blue = 8z^{-1

Required

Evaluate Blue when z = 9

To do this, we simply substitute 9 for z in Blue = 8z^{-1

Blue = 8 * 9^{-1

Convert indices to fraction

Blue = 8 * \frac{1}{9}

Blue = \frac{8}{9}

<em>Hence, the blue section has an area of </em>\frac{8}{9}ft^2<em></em>

3 0
3 years ago
What is the area of the composite figure?
d1i1m1o1n [39]
100cm2 that is the answer I got
4 0
3 years ago
Rosa saved $100 to spend on vacation. For the first 3 days of her vacation she spent $20 each day then for the next 2 days, afte
Wewaii [24]

Answer:

hope this helps you

6 0
2 years ago
Please help me solve this I forgot how to
RideAnS [48]
2.5 

hope it helps//...,d/cmn/lsjdhc;ljwknefv


4 0
3 years ago
QUESTION 1
Kitty [74]

It's difficult to make out what the force and displacement vectors are supposed to be, so I'll generalize.

Let <em>θ</em> be the angle between the force vector <em>F</em> and the displacement vector <em>r</em>. The work <em>W</em> done by <em>F</em> in the direction of <em>r</em> is

<em>W</em> = <em>F</em> • <em>r</em> cos(<em>θ</em>)

The cosine of the angle between the vectors can be obtained from the dot product identity,

<em>a</em> • <em>b</em> = ||<em>a</em>|| ||<em>b</em>|| cos(<em>θ</em>)   ==>   cos(<em>θ</em>) = (<em>a</em> • <em>b</em>) / (||<em>a</em>|| ||<em>b</em>||)

so that

<em>W</em> = (<em>F</em> • <em>r</em>)² / (||<em>F</em>|| ||<em>r</em>||)

For instance, if <em>F</em> = 3<em>i</em> + <em>j</em> + <em>k</em> and <em>r</em> = 7<em>i</em> - 7<em>j</em> - <em>k</em> (which is my closest guess to the given vectors' components), then the work done by <em>F</em> along <em>r</em> is

<em>W</em> = ((3<em>i</em> + <em>j</em> + <em>k</em>) • (7<em>i</em> - 7<em>j</em> - <em>k</em>))² / (√(3² + 1² + 1²) √(7² + (-7)² + (-1)²))

==>   <em>W</em> ≈ 5.12 J

(assuming <em>F</em> and <em>r</em> are measured in Newtons (N) and meters (m), respectively).

3 0
3 years ago
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