The Fibonacci sequence 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, … is formed by summing two consecutive numbers to get the next number.
adelina 88 [10]
By counting the combinations, we will see that there are 10 combinations such that the sum gives a Fibonacci number.
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How to count the combinations?</h3>
We have two number cubes with 6 outcomes each, such that we have a total of 36 combined outcomes.
For each dice, the outcomes are:
{1, 2, 3, 5, 8, 13}
Now, let's count the combinations that also give a Fibonacci number (these are given by adding two consecutive numbers in the sequence).
I will list each possible red outcome, then the blue outcomes that would give a Fibonacci term, and then we can count the number of combinations.
- Red Blue number of combinations.
- 1 2 1
- 2 1, 2 2
- 3 2, 3 2
- 5 3, 8 2
- 8 5, 13 2
- 13 8 1
Adding the numbers of combinations, we have:
C = 1 + 2 + 2 + 2 + 2 + 1 = 10
There are 10 combinations that give a Fubbonaci number.
If you want to learn more about combinations, you can read:
brainly.com/question/2280026
Answer:
x=(5c-3b)/a
Step-by-step explanation:
ax+3b=5c
or,ax=5c-3b
x=(5c-3b)/a
Answer:
Step-by-step explanation:
Answer: You have a better chance if you do not replace the red marble.
Step-by-step explanation:
The bag has:
5 red marbles
8 blue marbles
4 yellow marbles
3 green marbles
A total of 5 + 8 + 4 + 3 = 20
You want to draw a red marble and then a blue marble.
The probability of drawing a red marble in your first attempt is the number of red marbles divided the total number of marbles:
P1 = 5/20
now you want to draw a blue marble.
If you replace the red marble, you have 20 marbles again in the bag, then the probability of drawing a blue marble is:
P2 = 8/20
The joint probability is P = P1*P2 = (5/20)*(8/20) = 0.1
If you do not replace the red marble, you have 19 total marbles in the bag, then the probability of taking a blue marble is:
P2 = 8/19
The joint probability is:
P = P1*P2 = (5/20)*(8/19) = 0.105
The probability is slightly bigger if you do not replace the red marble.
