Question

35 over 6 equals negative 10 thirds(x minus 2)

Answer 1

$\text{Hey there!}$

$\mathsf{\dfrac{35}{6}=\dfrac{-10}{3}(x-2)}$

$\mathsf{Simplify\ both\ sides\ of\ your\ sides}$

$\mathsf{\dfrac{35}{6}=\dfrac{-10}{3}(x-2)}$

$\mathsf{\dfrac{-10}{3}(x)=\dfrac{-10}{3}x}$

$\mathsf{\dfrac{-10}{3}(-2)=\dfrac{20}{3}}$

$\mathsf{Your\ equation: \dfrac{35}{6}=\dfrac{-10}{3}x+\dfrac{20}{3}}$

$\mathsf{Flip\ the\ equation\ around}$

$\mathsf{\dfrac{-10}{3}+\dfrac{-10}{3}x=\dfrac{35}{6}}$

$\mathsf{SUBTRACT\ both\ sides\ by\ \dfrac{20}{3}\ on\ both\ of\ your\ sides}$

$\mathsf{\dfrac{-10}{3}x+\dfrac{20}{3}-\dfrac{20}3{}=\dfrac{35}{6}-\dfrac{20}{3}}$

$\mathsf{Cancel\ out: \dfrac{20}{3}-\dfrac{20}{3}\ because\ it\ equals\ to\ 0}$

$\mathsf{\dfrac{35}{6}-\dfrac{20}{3}=\dfrac{-5}{6}}$

$\mathsf{\dfrac{-10}{3}x=\dfrac{-5}{6}}$

$\mathsf{MULITPLY\ both\ of\ your\ sides\ by\ \dfrac{3}{-10}}$

$\mathsf{\dfrac{3}{-10}\times\dfrac{-10}{3}x=\dfrac{3}{-10}x\times\dfrac{-5}{6}}$

$\mathsf{Cancel\ out: \dfrac{3}{-10}\times\dfrac{-10}{3}\ because\ it\ gives\ us\ 1}$

$\mathsf{\dfrac{3}{-10}\times\dfrac{-5}{6}=x}$

$\mathsf{SOLVE\ above\ \uparrow\ and\ you\ have\ the\ value\ of\ x}$

$\boxed{\boxed{\mathsf{Thus, \ your\ answer\ is: x=\dfrac{1}{4}}}}\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~$\dfrac{\frak{LoveYourselfFirst{}}}{:)}$

Answer 2

When you solve for “x”, you must complete the opposite function on both sides of the equals sign to cancel values out and isolate “x”

For example:
x+2=3
It’s
x+2-2=3-2
x=1

In this equation:
35/6 = -10/3(x-2)
35/6 divided by -10/3 = x-2
Now to divide these fractions, find the inverse of one fraction and multiply them together (-10/3 inverse is 3/-10):
35/6 • 3/-10 = x-2
105/-60 = x-2
-1.75 = x-2
-1.75 + 2 = x
0.25 = x