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Anestetic [448]
3 years ago
9

Please Please please help me with this answer asap

Mathematics
1 answer:
Ahat [919]3 years ago
8 0
The answer is 19 packages of popsicles. You would multiply 19 and 3 and get 57. After you get 57 you subtract 3 and end up with 54
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You purchased $132.49 worth of wheels and bearings for your skateboards. The shop charges $15 per board to install them. The tot
Mila [183]

4 skateborards will be repaired

4 0
3 years ago
Find the axis of symmetry for this parabola: <br><br> y=-5x^2-10x-13
Dmitry [639]

Answer:

x=1

Step-by-step explanation:

1. Complete the square on the right side of the equation.

5 ( x − 1 )2 − 18

2. Use the vertex form,  y = a ( x − h ) 2 + k , to determine the values of  a ,  h , and  k . a= 5 h = 1 k = − 18

3. Since the value of  a  is positive, the parabola opens up.

Opens Up

4. Find the vertex  ( h , k ) . ( 1 , − 18 )

5. Find  p , the distance from the vertex to the focus.

1 /20

6. Find the focus.

7. ( 1 , − 359/ 20 )

8. Find the axis of symmetry by finding the line that passes through the vertex and the focus.

ANSWER: x = 1

6 0
3 years ago
A sphere has a radius of 4 in. Which equation finds the volume of the sphere?
Ede4ka [16]

Volume : 4πR³/3


R=4


↓


V = 4π·4³/3                   or                   \frac{4}{3}*\pi  *(4)^{3}



5 0
4 years ago
Read 2 more answers
What are the possible values of x if (4x-5)^2=49? check all that apply. -4/5, -1/2, 3, 5, 7
vesna_86 [32]
The values are just 3 and -1/2 and that is all (:
5 0
3 years ago
Read 2 more answers
According to DeMorgan 's theorem, the complement of W · X + Y · Z is W' + X' · Y' + Z'. Yet both functions are 1 for WXYZ = 1110
sergeinik [125]

Answer:

The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.

Step-by-step explanation:

According to DeMorgan's Theorem:

(W.X + Y.Z)'

(W.X)' . (Y.Z)'

(W'+X') . (Y' + Z')

Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.

For the original function:

(W . X + Y . Z)'

= (1 . 1 + 1 . 0)

= (1 + 0) = 1

For the compliment:

(W' + X') . (Y' + Z')

=(1' + 1') . (1' + 0')

=(0 + 0) . (0 + 1)

=0 . 1 = 0

Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.

Without the parenthesis the compliment equation looks like this:

W' + X' . Y' + Z'

1' + 1' . 1' + 0'

0 + 0 . 0 + 1

Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.

Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.

3 0
3 years ago
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