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max2010maxim [7]
3 years ago
15

Help me with this please ​

Mathematics
1 answer:
OleMash [197]3 years ago
8 0

Answer:

x=4

Step-by-step explanation:

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Two angles in a triangle have measures of 18 and 77º.<br> What is the measure of the third angle
kow [346]

Answer:

85 ° is the answer to the question

7 0
3 years ago
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For the right triangles below, find the exact values of the side lengths and .
konstantin123 [22]

Answer:

c=\frac{2\sqrt{3}}{3}

h=3\sqrt{2}

Step-by-step explanation:

Please see the attached image. It is a good idea it to memorize these triangle properties because you will definitely use them in the future.

c=\frac{2}{\sqrt{3} } =\frac{2*\sqrt{3} }{\sqrt{3} *\sqrt{3} } =\frac{2\sqrt{3}}{3}

h=3\sqrt{2}

5 0
3 years ago
What is the gcf of 18a, 20ab, and 6ab
riadik2000 [5.3K]
Greatest common factor
faceor each and find common groups
18a=2 times 3 times 3 times a
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7 0
3 years ago
Find the fifth roots of 32(cos 280° + i sin 280°)
shusha [124]

Answer:

The fifth root is 2[cos(56°) + i sin(56°)]

Step-by-step explanation:

* To solve this problem we must revise De Moiver's rule

- In the complex number with polar form

∵ z = r(cosФ + i sinФ)

∴ z^n = r^n(cos(nФ) + i sin(nФ))

* In the problem

- The fifth root means z^(1/5)

- We can put 32 as a form a^n

∵ 32 = 2 × 2 × 2 × 2 × 2 = 2^5

∴ z = 2^5[cos(280°) + i sin(280°)]

* Lets find z^(1/5)

*z^{\frac{1}{5}}=[2^{5}]^{\frac{1}{5} } (cos(\frac{1}{5})(280)+isin(\frac{1}{5})(280)

*(2^{5})^{\frac{1}{5}}=2^{5.\frac{1}{5}}=2

∴ z^(1/5) = 2[cos(56) + i sin(56)]

* The fifth root of 32[cos(280°) + i sin(280°)] is 2[cos(56°) + i sin(56°)]

 

4 0
3 years ago
What is 12 divided by -10?
Natasha_Volkova [10]
It would be -1.2
hope i helped follow me
8 0
3 years ago
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