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2 years ago

If a rectangular. Prism. Has 5cm. 10cm on one side and 4cm on the. Other. What is the volume of the rectangle?

Mathematics

1 answer:

emmasim [6.3K]2 years ago

7 0

Answer: $200\ cm^3$

Step-by-step explanation:

Given

The dimension of the rectangular prism is

$l=5\ cm\\w=10\ cm\\h=4\ cm$

The volume of the prism is given by $V=l\times w\times h$

$\Rightarrow V=5\times 10\times 4\\\Rightarrow V=200\ cm^3$

Therefore, the volume of the prism is $200\ cm^3$ .

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Step-by-step explanation:

Given

Radius r=15 cm

distance of chord from the center is 10 cm

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Illusion [34]

Given:

Total number of students = 27

Students who play basketball = 7

Student who play baseball = 18

Students who play neither sports = 7

To find:

The probability the student chosen at randomly from the class plays both basketball and base ball.

Solution:

Let the following events,

A : Student plays basketball

B : Student plays baseball

U : Union set or all students.

Then according to given information,

$n(U)=27$

$n(A)=7$

$n(B)=18$

$n(A'\cap B')=7$

We know that,

$n(A\cup B)=n(U)-n(A'\cap B')$

$n(A\cup B)=27-7$

$n(A\cup B)=20$

Now,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=7+18-n(A\cap B)$

$n(A\cap B)=7+18-20$

$n(A\cap B)=25-20$

$n(A\cap B)=5$

It means, the number of students who play both sports is 5.

The probability the student chosen at randomly from the class plays both basketball and base ball is

$\text{Probability}=\dfrac{\text{Number of students who play both sports}}{\text{Total number of students}}$

$\text{Probability}=\dfrac{5}{27}$

Therefore, the required probability is $\dfrac{5}{27}$ .

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3 years ago