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Radda [10]
3 years ago
5

Destin walked 2km and Jane walked 4,000 ft. What is the approximate combined distance they walked? Note: 1 Foot (ft) is equal to

0.0003048 kilometer (km).
A 1 of a mile 5
B 50 yards
C 2 miles
D) 5 kilometers​
Mathematics
1 answer:
Anna11 [10]3 years ago
3 0

Answer: Option C.

Step-by-step explanation:

The data is:

Destin walked 2km

Jane walked 4000ft.

Let's write both of those in the same units.

The data given is:

1ft = 0.0003048km.

and 4000ft is 4000 times that:

4000ft = 4000*1ft = 4000*0.0003048km = 1.22km

Then if we add those, we get:

Total distance = 2km + 1.22km = 3.22km

So we can already discard option D.

Now, we know that:

1km = 0.6214 miles.

then 3.22 km is 3.22 times that amount:

3.22km = 3.22*1km = 3.22*(0.6214 mi) = 2 miles

The correct option is C.

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In a study relating the degree of warping, in mm, of a copper plate (y) to temperature in °C (x), the following summary statisti
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Answer:

a)

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b)

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Step-by-step explanation:

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We need to find an equation of the form

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The slope m can be computed with the formula

\bf m=\displaystyle\frac{\displaystyle\sum_{i=1}^n(x_i-\bar x)(y_i-\bar y)}{\displaystyle\sum_{i=1}^n(x_i-\bar x)^2}

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We simply replace x with 40 to get

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c. At what temperature will we predict the warping to be 0.5 mm? Round the answer to two decimal places

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0.5 = 0.3035 + 0.0082x ===> x = (0.5-0.3035)/0.0082 ===>

 

x = 23.9634 °C

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