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Verdich [7]
2 years ago
10

tandard automobile license plates in a country display 1 numbers, followed by 2 letters, followed by 4 numbers. How many differe

nt standard plates are possible in this system? (Assume lead 0 is not allowed, but repetitions of letters and numbers are allowed.)

Mathematics
1 answer:
kolbaska11 [484]2 years ago
8 0

Answer:

39,917,124

Step-by-step explanation:

In order to solve this problem we must start by drawing a diagram of what the licence plates look like. (See Attached picture).

Now, each box in the picture will represent one digit of the plate. Some must be numbers and some must be letters. We know we have 9 posibilities for theh numbered boxes (1-9) and we have 26 possibilities for the boxes that are to contain letters. Repetitions allowed. So the possible character for each box is as follows:

box 1 = 1 to 9 = 9

box 2 = A to Z = 26

box 3 = A to Z = 26

box 4 = 1 to 9 = 9

box 5 = 1 to 9 = 9

box 6 = 1 to 9 = 9

box 7 = 1 to 9 = 9

so the total number of licence plates can be found by multiplying the possibilities for each box in the plate so we get:

# of plates = (9)(26)(26)(9)(9)(9)(9)

which can be simplified to:

plates= 9^{5}26^{2}=39,917,124

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Answer:

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Step-by-step explanation:

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2 years ago
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Olin [163]
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3 years ago
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romanna [79]

Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

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Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

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a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

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\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

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3 years ago
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olga2289 [7]
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2 years ago
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Answer:

C) (14, 8, 10)

Step-by-step explanation:

the values in the parentheses go in order of the letters in the first equation

all you have to do is plug in the values

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p-r=4. (14)-(10)=4

2p+q=36. 2(14)+(8)=36

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