5/4+x/2 =3 Hey can someone explain this please!

Mathematics

1 answer:

Vikentia [17]3 years ago

3 0

Answer:

x = $\frac{7}{2}$

Step-by-step explanation:

Given

$\frac{5}{4}$ + $\frac{x}{2}$ = 3 ( multiply through by 4 to clear the fractions )

5 + 2x = 12 ( subtract 5 from both sides )

2x = 7 ( divide both sides by 2 )

x = $\frac{7}{2}$

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(1 - cos ß)(1 + cos ß) =1/cosec^2(ß)

iVinArrow [24]

Step-by-step explanation:

L.H.S=(1-cosB)(1+cosB)

=(1-cos^2B). {using (a+b) (a-b)=(a^2-b^2)in second step}

=sin^2B

=1/cosec^2B

Therefore,L.H.S=R.H.S proved

5 0

3 years ago

Suppose that E and F are two events and that P(E)=0.3 and P(F|E)=0.5. What is P(E and F)?

Sergio [31]

E and F are two events and that P(E)=0.3 and P(F|E)=0.5. Thus, P(E and F)=0.15

Bayes' theorem is transforming preceding probabilities into succeeding probabilities. It is based on the principle of conditional probability. Conditional probability is the possibility that an event will occur because it is dependent on another event.

P(F|E)=P(E and F)÷P(E)

It is given that P(E)=0.3,P(F|E)=0.5

Using Bayes' formula,

P(F|E)=P(E and F)÷P(E)

Rearranging the formula,

⇒P(E and F)=P(F|E)×P(E)

Substituting the given values in the formula, we get

⇒P(E and F)=0.5×0.3

⇒P(E and F)=0.15

∴The correct answer is 0.15.

If, E and F are two events and that P(E)=0.3 and P(F|E)=0.5. Thus, P(E and F)=0.15.

Learn more about Bayes' theorem on