Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
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* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
The consecutive positive integers would be: x and (x+1),
We would have to solve the following equation to find these numbers:
x(x+1)-[x+(x+1)]=29
x²+x-2x-1=29
x²-x-30=0
x=[1⁺₋√(1+120)]/2
x=(1⁺₋11)/2
We have two possible solutions:
x₁=(1-11)/2=-5 then: (x+1)=-5+1=-4 This is not the solution.
x₂=(1+11)/2=6 then: (x+1)=6+1=7 This solution is right.
Answer: the numbers would be 6 and 7.
Here, My initial salary = 7.85
FICA deduction amount = 7.85 * 7.65% = 7.85 * 0.0765 = 0.60
Federal Tax amount = 7.85 * 9.8% = 7.85 * 0.098 = 0.77
State tax amount = 7.85 * 5.5% = 7.85 * 0.055 = 0.43
So, Total deducted amount = 0.60 + 0.77 + 0.43 = 1.80
Net hourly wage = 7.85 - 1.80 = 6.05
In short, Your Answer would be $6.05
Hope this helps!
y- intercept = (0, 4), x-intercept = (- 2, 0)
to find the intercepts let x = 0 and y = 0 in the equation
x = 0 → y = 0 + 4 =4 ⇒ y-intercept (0, 4)
y = 0 → 2x + 4 = 0 ⇒ x = - 2 ⇒ x- intercept(- 2, 0)
Answer:
A (no because the graph is not a straight line)
Step-by-step explanation:
The rate of change is not consistent, and therefor is not proportional.
