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Luden [163]
3 years ago
7

V1-v2\t solve formula for v1

Mathematics
1 answer:
vitfil [10]3 years ago
8 0

Answer:

Uwm am I famous but I'm doin dis for free points sowwy

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The amount of money Chaz earned for walking dogs is given in the table. Can the relationship be described by a constant rate? Ex
mojhsa [17]

Answer:

Yes, the relationship can be described by a constant rate of $18.75 per dog

Step-by-step explanation:

see the attached figure to better understand the problem

Let

x ----> the number of dogs

y ---> the amount of money earned

we have the points

(6,112,50), (8,150), (11,206.25)

step 1

Find the slope with the first and second point

(6,112,50), (8,150)

m=(150-112.50)/(8-6)=18.75

step 2

Find the slope with the first and third point

(6,112,50), (11,206.25)

m=(206.25-112.50)/(11-6)=18.75

Compare the slopes

The slopes are the same

That means, that the three points lies on the same line

therefore

Yes, the relationship can be described by a constant rate of $18.75 per dog

7 0
3 years ago
Plz help with this math problem
Virty [35]
Re-upload the photo you posted because it isnt showing up :(
4 0
3 years ago
PLS HELP! 7x +10y= -23<br><br> 7x + 6y = - 39
mote1985 [20]
4y = -23 + 39
4y = 16
y = 4

Sub y = 4 into equation 2
7x + 6(4) = -39
7x + 24 = -39
7x = -39-24
7x = -63
x = -9

x = -9
y = 4
5 0
3 years ago
Given that f(x) = x2 + 3x + 6 and g(x) = the quantity of x plus two, over three, solve for f(g(x)) when x = 1
MaRussiya [10]
Easy
f(g(1))
evaluate g(1) then plug thatin for x in f(x)
g(1)=(x+2)/3
g(1)=(1+2)/3
g(1)=1

f(g(1))=
f(1)=(1)^2+3(1)+6
f(1)=1+3+6
f(1)=10
f(g(1))=10
3 0
3 years ago
Read 2 more answers
Write the standard form of the equation of the circle that passes through the point
AnnZ [28]

Answer:

The standard form of the equation of the circle is x^2+y^2=1.

Step-by-step explanation:

A circle is the set of points in a plane that lie a fixed distance, called the radius, from any point, called the center.

The equation of a circle in standard form is

                                             (x-h)^2+(y-k)^2=r^2

where <em>r</em> is the radius of the circle,  and <em>h</em>, <em>k</em> are the coordinates of its center.

When the center of the circle coincides with the origin h=k=0, so

                                            (x-0)^2+(y-0)^2=r^2\\x^2+y^2=r^2

We are also told that the circle contains the point  (0, 1), so we will use that information to find the radius <em>r</em>.

                                                   0^2+1^2=r^2\\r^2=0^2+1^2\\r^2=1\\r=\sqrt{1}

Therefore, the standard form of the equation of the circle is x^2+y^2=1.

5 0
3 years ago
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