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3 years ago

Which equation has infinitely many solutions?

Mathematics

1 answer:

ipn [44]3 years ago

4 0

Answer:

Equation C. 5.1 + 2y + 1.2 = -2 + 2y + 8.3

Step-by-step explanation:

Equation C is the only equation in the list in which the terms that contain the unknown "y" on each side of the equal sign are identical, therefore when solving for this unknown and trying to group them on one side, they go away, leaving us with a relationship among numerical values that is always true:

5.1 + 2y + 1.2 = -2 + 2y + 8.3

5.1 + 1.2 = -2 + 8.3

6.3 = 6.3

Then this equation is true for any value of the unknown y, and y- can adopt infinite number of values, independent of which the equation will always be a true statement (giving thus infinite number of solutions).

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Please help this is due today and I can't figure it out!!!<br>Also explain your answer.

Tasya [4]

Answer:

Ratio (red to blue ) of the perimeters: $\frac{11}{6}$

Ratio (red to blue ) of the areas: $\frac{121}{36}$

Step-by-step explanation:

In similar figures

The ratio between their corresponding sides equal to the ratio between their perimeters

The square the ratio between their corresponding sides equal to the ratio between their areas

Let us solve the question

∵ The red figure and the blue figure are similar

∴ Their corresponding sides have equal ratios

∵ Two corresponding sides are 11 and 6

∴ The ratio of similarity (red to blue) = $\frac{11}{6}$

→ By using the first rule above

∵ The ratio of their perimeters = the ratio of the corresponding sides

∴ The ratio of their perimeters (red to blue) = $\frac{11}{6}$

∴ Ratio (red to blue ) of the perimeters: $\frac{11}{6}$

→ By using the second rule above

∵ The ratio of their areas = Square the ratio of their sides

∴ The ratio of their areas (red to blue) = ( $\frac{11}{6}$ )²

∴ The ratio of their areas (red to blue) = $\frac{121}{36}$

∴ Ratio (red to blue ) of the areas: $\frac{121}{36}$

6 0

3 years ago

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Vitek1552 [10]

The answer is C because the square root equals to 2.8 and it is the closest one to the point shown

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3 years ago

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4 years ago

Finding value of each variable in the parallelogram

Galina-37 [17]

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3 years ago

*Geometry Question*

Anvisha [2.4K]

Answer:

P'(1, 1), Q'(2, 2), R'(4, 1)

Step-by-step explanation:

The dilation factor multiplies each coordinate value, so ...

P' = (1/2)P = (2/2, 2/2) = (1, 1)

Q' = (1/2)Q = (4/2, 4/2) = (2, 2)

R' = (1/2)R = (8/2, 2/2) = (4, 1)

Each point is half as far from the origin as the original. Here, all of the PQR coordinates are even numbers, so dividing them by 2 is about as easy as it gets.

3 0

4 years ago