Which equation has infinitely many solutions?

Mathematics

1 answer:

ipn [44]2 years ago

4 0

Answer:

Equation C. 5.1 + 2y + 1.2 = -2 + 2y + 8.3

Step-by-step explanation:

Equation C is the only equation in the list in which the terms that contain the unknown "y" on each side of the equal sign are identical, therefore when solving for this unknown and trying to group them on one side, they go away, leaving us with a relationship among numerical values that is always true:

5.1 + 2y + 1.2 = -2 + 2y + 8.3

5.1 + 1.2 = -2 + 8.3

6.3 = 6.3

Then this equation is true for any value of the unknown y, and y- can adopt infinite number of values, independent of which the equation will always be a true statement (giving thus infinite number of solutions).

You might be interested in

No bots answer fast plz 1. (4x + 8) + (7x + 3) =

Delicious77 [7]

12x + 11

………………………………….

3 0

2 years ago

Read 2 more answers

In a certain Algebra 2 class of 29 students, 7 of them play basketball and 14 of them

Mariulka [41]

Answer:

Two possible answers below

Step-by-step explanation:

Probability and Sets

We are given two sets: Students that play basketball and students that play baseball.

It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.

This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

$\displaystyle P=\frac{19}{29}$

P = 0.66

Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:

We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.

Thus, there 19-2=17 students who play only one of the sports. The probability is:

$\displaystyle P=\frac{17}{29}$