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3 years ago

5

frank is wrapping a present. the box measures 6 cm wide by 9 cm long by 5.1 cm tall.what amount of wrapping paper,not counting o

verlap ,will frank need

1 answer:

Montano1993 [528]3 years ago

3 0

(2 × (6cm x 9cm)) + (2 × (6cm x 5.1cm)) + (2 × (9cm x 5.1cm)) = 261 square cm

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one container holds a 1 7/8 quarts of water and a second container holds 5 3/4 quarts of water. how many more quarts of water do

dimulka [17.4K]

So lets solve this!

Quarts of water 1st container holds= 17/8

Quarts of water 2nd container holds= 5 3/4

Quarts of water does the second container holds than the first container=?

First of all we need to change 5 3/4 into an improper fraction

5 3/4= 23/4

Secondly, we need to find the LCM of 17/8 and 23/4

LCM:

17/8= 51/24

23/4= 138/24

So now we have got both of the LCM's

Quarts of second container holds the first container= 23/4 - 138/24=87/24

Your answer is 87/24

Hope this Helps!

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3 years ago

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So the probability of drawing these two particular cards in the given order is

$\dfrac{12}{52}\cdot\dfrac4{51}=\dfrac4{221}$

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