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2 years ago

1/2 4/3 9/4 16/5 find the nth term of this sequence

Mathematics

1 answer:

Phantasy [73]2 years ago

4 0

The nth number is 81 /10.

Steps:
You multiple the denominator by itself

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Can someone tell me the answer

astra-53 [7]

Answer:

-3

Step-by-step explanation:

(-6)/(+2)

-6/+2

-3

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3 years ago

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100serihttps://brainly.com/question/23752325#

d1i1m1o1n [39]

Answer:

what?

Step-by-step explanation:

7 0

2 years ago

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Solve for x.<br><br> x=<br><br> Look at image

postnew [5]

Answer:

$x = 14$

Step-by-step explanation:

To find x, the following equation is generated given the available information:

$\frac{(x + 7) + x)}{x + 7} = \frac{12 + 8}{12}$

$\frac{2x + 7}{x + 7} = \frac{20}{12}$

$\frac{2x + 7}{x + 7} = \frac{5}{3}$

Cross multiply

$3(2x + 7) = 5(x + 7)$

$6x + 21 = 5x + 35$

Collect like terms

$6x - 5x = - 21 + 35$

$x = - 21 + 35$

$x = 14$

8 0

2 years ago

100 POINTS AND BRAINLIEST

zysi [14]

Answer:

8 square units and $\frac{40}{3}$ square units

Step-by-step explanation:

The area of the triangle ABC is 24 square units.

1. Triangles ABC and FBG are similar with scale factor $\frac{1}{3},$ then

$\dfrac{A_{\triangle FBG}}{A_{\triangle ABC}}=\dfrac{1}{9}\Rightarrow A_{\triangle FBG}=\dfrac{1}{9}\cdot 24=\dfrac{8}{3}\ un^2.$

2. Triangles ABC and DBE are similar with scale factor $\frac{2}{3},$ then

$\dfrac{A_{\triangle DBE}}{A_{\triangle ABC}}=\dfrac{4}{9}\Rightarrow A_{\triangle DBE}=\dfrac{4}{9}\cdot 24=\dfrac{32}{3}\ un^2.$

3. Thus, the area of the quadrilateral DFGE is

$A_{DFGE}=A_{\triangle DBE}-A_{\triangle FBG}=\dfrac{32}{3}-\dfrac{8}{3}=8\ un^2.$

and the area of the quadrilateral ADEC is

$A_{ADEC}=A_{\triangle ABC}-A_{\triangle DBE}=24-\dfrac{32}{3}=\dfrac{40}{3}\ un^2.$

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2 years ago

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What would you do to isolate the variable in the equation below, using only one

weeeeeb [17]

Subtract 9 from both sides of the equation

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2 years ago

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