No. This is not random sampling as the students chose are not chosen at random. Random sampling would be something done where each sample has equal probability of being chosen. Clearly this is not random sampling.
Answer:
3 sheets
Step-by-step explanation:
he used one of each,red,green and white
6 4/5 + 6 4/5 + 2 2/3 + 2 2/3 = 18 14/15
When multiplying fractions just multiply the numerator and denominators together, then simplify the fraction you get.
To solve the addition problem, first convert 2 and 1/2 to an improper fraction. It should be 5/2. Now 3/8 and 5/2 must be added together.
To add these, they must have the same denominator. Let's give 5/2 a denominator of 8, so it matches 3/8.
To give 5/2 a denominator of 8, you are starting with a denominator of 2. 2 × 4 = 8, so you must multiply 5/2 by 4.
You should get 20/8. Now you have to add 20/8 and 3/8. The only thing you add is the numerator, so you should get 23/8 as a final answer.
For the subtraction problem, do these same steps to make the fractions you must subtract have the same denominator, then subtract only the numerator to get the answer. Once you solve the subtraction problem, text me what you got so I can check it for you. :)
Answer: a. The correlation coefficient of the data is positive.
Step-by-step explanation:
Estimated slope of sample regression line = 
Here , confidence interval : (-0.181, 1.529)
Estimated slope of sample regression line = 
![=\dfrac{1.348}{2}\\\\=0.674\ \ \ \ [\text{ positive}]](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1.348%7D%7B2%7D%5C%5C%5C%5C%3D0.674%5C%20%5C%20%5C%20%5C%20%5B%5Ctext%7B%20positive%7D%5D)
⇒Correlation coefficient(r) must be positive, So a. is true.
But, d. and e. are wrong(0.674 ≠ 0 or 1.348).
We cannot check residuals or its sum from confidence interval of slope of a regression line, so b is wrong.
We cannot say that scatterplot is linear as we cannot determine it from interval, so c. is wrong
So, the correct option : a. The correlation coefficient of the data is positive.
