Answer:
(a) Orthogonal, (b) Neither, (c) Parallel, d( Orthogonal
Step-by-step explanation:
a and b are parallel is a=kb
a and b if a dot b = 0
(a) a dot b = (9)(-4)+6(6)=-36+36=0
a and b are orthogonal
(b) a dot b = 40-7-21=12
a=kb -> there is no k value satisfying the equation
a and b are neither parallel or orthogonal
(c) a dot b = -12-108-48=-168
a=kb -> k=-3/4 satisfies the equation
a and b are parallel
(d) a dot b= 9-3-6=0
a and b are orthogonal
The solution to the answer is as follows:
<span>0votes</span><span>answered <span>Aug 8, 2015 </span><span><span>by </span>Shashi Kumar Evangelist <span>(3,082<span> points)</span></span></span></span><span>total coins 30
1 rupee coins 20
50 paise coins 10
1 rupee coin probability 20C11
11 coin are picked 30C11
<span>ans should be = 20C11/30C11 = 2/3</span></span>
I hope my answer has come to your help. God bless and have a nice day ahead!
Answer:
(B) 3265.50
Step-by-step explanation:
.07 * 46650 = 3265.5
Hope this helps!!!!! :)
<span>The value 28 should have been rounded to 2×101
</span>
Answer:
see explanation
Step-by-step explanation:
If A +B = 45° then tan(A+B) = tan45° = 1
Expanding (1 + tanA)(1 + tanB)
= 1 + tanA + tanB + tanAtanB → (1)
Using the Addition formula for tan(A + B)
tan(A+B) = = 1 ← from above
Hence
tanA + tanB = 1 - tanAtanB ( add tanAtanB to both sides )
tanA + tanB + tanAtanB = 1 ( add 1 to both sides )
1 + tanA + tanB + tanAtanB = 2
Then from (1)
(1 + tanA)(1 + tanB) = 2 ⇒ proven