The proportional relationship should require they y-intercept and is then 0 and the linear relationship should be in a straight line to be a linear! Hope this helps!
the answer of the question is tens
Questions (contd)
(a) For what amount of driving do the two plans cost the same?
(b) What is the cost when the two plans cost the same?
Answer:
(a) 100 miles
(b) $65
Step-by-step explanation:
Given
Plan 1:

per mile
Plan 2:

per mile
Solving (a): Number of miles when both plans are equal
Represent the distance with x and the cost with y
So:
Plan 1:

Plan 2:

To solve (a), we equate both plans together; i.e.


Collect Like Terms


Solve for x


Hence, 100 mile would cost both plans the same
Solving (b): Cost when both plans are the same:
In this case, we simply substitute 100 for x in any of the y equation.




<em>Hence, the amount is $65</em>
The ball hits the ground when the height h(t) = 0 , so
-16t^2 + 80t = 0
-16t(t - 5) = 0
t- 5 = 0 or -16t^2 = 0 ( here t = 0 which corresponds to when ball is thrown)
t - 5 = 0 gives:-
t = 5 seconds (answer)
A=2...
Subtract 14 from both sides,then subtract 8 from both sides. Your left with
6a=12
6x1=6
6x2=12
A=2