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zheka24 [161]
3 years ago
10

Which pair shows equivalent expression

Mathematics
1 answer:
Elza [17]3 years ago
6 0

Answer:

3(x+2) = 3x + 6

Step-by-step explanation:

An equivalent expression is an expression that is equal. You need to find if the left and right side of the equal signs are equal to each other by reducing each to simplest terms.

Each of the expressions can be multiplied to find lowest terms by removing the parenthesis.

So 3(x+2) becomes 3x + 6

So x^2(3 + 2) becomes 3x^2 + 2x^2

So 3(x+2) becomes 3x + 6

-3(2+x) = -6 - 3x

Only A has equivalent or equal expressions.

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Yall please help meee
madam [21]

Answer-

x=0;y=3

x=1;y=-1

x=2;y=-5

x=3;y=-9

7 0
3 years ago
Daisha is sitting on the bus on the way home from school and is thinking
Zina [86]

Answer:

Step-by-step explanation:

P(of an event)=No. of possibilities of the event/total no. of events

a)P(completes exactly one assignment)=1/3

b) P(completes more than one assignment)=2/3

c)P(at least one assignment)=3/3=1

5 0
3 years ago
A figure is composed of a rectangle and a right triangle. What is the area of the figure?
strojnjashka [21]

QUESTION 1

The figure is a tra-pezoid.

The area of a trapezoid is given by the formula;

A=\frac{1}{2}(Sum\:of\:parallel\:sides)\times h

We substitute the values to obtain;

Area=\frac{1}{2}(13.2cm+8.4cm)\times 6cm

Area=\frac{1}{2}(21.6cm)\times 6cm

Area=64.8cm^2

QUESTION 2

The approximate length of the ribbon is equal to the circumference of the circular table cloth.

We can find this by using the formula for calculating the circumference of a circle.

C=2\pi r

where r=3.5ft is the radius of the circular table cloth.

We substitute this value and \pi=3.14 into the formula to get;

C=2(3.14)(3.5)ft

C=21.98ft

The approximate length of the ribbon is 22.0ft to the nearest tenth.

QUESTION 3

Type of quadrilateral:Rectangle

Explanation: A rectangle has 4 angles that are right angles.

The two pairs of opposite sides of a rectangle are also congruent.

QUESTION 4.

The circumference of a semi circle is calculated using the formula;

C=\pi r

where r=12.5cm is the radius of the semicircle.

C=3.14\times 12.5cm

C=39.25cm

QUESTION 5

The area of the entire figure is the area of the semicircle plus the area of the isosceles triangle.

Area=\frac{1}{2}\pi r^2+\frac{1}{2}bh

Area=\frac{1}{2}\times3.14\times12.5^2+\frac{1}{2}\times25\times 24

Area=345.3125+300

Area=645.3125cm^2

Area\approx645cm^2

QUESTION 6

The area of the parallelogram is given by the formula;

A=bh

From the diagram, b=y\:in.,h=3in..

Given, A=23.7 inches squared.

We substitute the values to obtain;

23.7=3y

y=\frac{23.7}{3}

y=7.9in.

QUESTION 7

The area of a rectangle is given by the formula;

Area=l\times b

The area of the bigger rectangle =9\times15=135in^2

The area of the smaller rectangle =8\times 13=104in^2

The area of the  shaded region =135-104=31in^2

5 0
3 years ago
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