The closest distance between point A and point A' is 8.5 ⇒ B
Step-by-step explanation:
Let us revise the translation of a point
- If the point (x , y) translated horizontally to the right by h units then its image is (x + h , y)
- If the point (x , y) translated horizontally to the left by h units then its image is (x - h , y)
- If the point (x , y) translated vertically up by k units then its image is (x , y + k)
- If the point (x , y) translated vertically down by k units then its image is (x , y - k)
∵ Point A is located at (-5 , 2)
∵ Point A is translated 8 units to the right and 3 units up
- That means add x-coordinate by 8 and add y-coordinate by 3
∴ Point A' located at (-5 + 8 , 2 + 3)
∴ Point A' located at (3 , 5)
The distance between two points
and 
is 
∵ Point a = (-5 , 2) and point A' = (3 , 5)
∴
= -5 and
= 3
∴
= 2 and
= 5
- Substitute these values in the rule of the distance
∵ 
∴ 
∴ 
∴ 
∴ d = 8.544 ≅ 8.5
The closest distance between point A and point A' is 8.5
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Answer:
Solutions of x are;
x = -7 + 8i and x = -7 -8i
Step-by-step explanation:
Given the equation: 
Add 96 both sides we get;


Using quadratic formula
then the solution is given by:

On comparing we have;
a= 1, b =14 and c =113


or

Simplify:
; where i is the imaginary, 
or

Therefore, the solution of x are; x = -7 + 8i and x = -7 -8i
The answer would be n<=-15
This is the formula to find the amt. A of that radioactive substance after time t.

We want to find out low long it will take for A to become half of its original amount.
We don't know the original amount, and the substance is not decaying at a constant rate (but rather an exponential one) so we can't answer that question.
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