Answer:
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Step-by-step explanation:
4 is greater than 3
sqrt15 is greater than sqrt6
So 4+sqrt15 must be greater than 3+sqrt6
the zero(s) of function 
is x=2
Step-by-step explanation:
We need to find the zero(s) of function algebraically.
We are given:
To find the zeros we put the function equal to zero.
So, the zero(s) of function is x=2
Keywords: zero(s) of function
Learn more about zero(s) of function at:
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Answer:
Step-by-step explanation:
For the first one, you have to convert the fractions to an improper fraction. To do that you need to multiply the bottom denominator number (3) by the whole number (1) then you need to add the numinator, so 3x1+2= 5. You have to keep the denominator so 1 2/3 is equal to 5/3. Then do the same to 2 1/5, and you get 11/5. Now you have to find a common denominator, that's basically the smallest number that both numbers can go Into, the lowest common denominator for 3 and 5 is 15. So 3x5= 15, so we have to multiply the top number by 5 which is 25. So 5/3 is equal to 25/15, then 5x3= 15, so you need to multiply 11 by 3 which is 33. So 11/5 is equal to 33/15. Then you add them. Add the numinators (25+33=58. Then you keep the denominator 15. So when u add it it's 58/15 then you need to simplify that and you get 3 13/15.
The second one you turn them into improper fractions like I told you how to before (multiply the bottom number by the whole number then add he top number, then add he same denominator.) do that for both. Then you line them right next to each other and multiply across. (I just realized that they were the same number so they are equal to 5/3 and 11/5)
Then you do 5x11 and you get 55 then do 3x5 and you get 15. 55/15 is your answer, but you need to simplify it, you need to divide 55 by 15, (not all the way just the first number) so you do 15x3 and that's 45, then you subtract that from 55, and you get 10, so then you take your denominator (15) and you answer is 3 10/15. But when you simplify it it's 3 and 2/3
Hope I helped sorry it's so long and sorry for any typos it's so long I didn't go back and check
If the pentagon is rotated 360° about the origin, that means the new figure will be exactly in the same position as the original image, because a rotation of 360° about the origin doesn't change the figure position or orientation.
So, if the vertex was located at (10, -8), the new figure will also have a vertex located at (10, -8).
Therefore the correct option is the fourth one.
