3 years ago

Help pleasee!! this is due tomrw I need answers asap!!

Mathematics

1 answer:

Mashutka [201]3 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

In a Gallup poll, 1025 randomly selected adults were surveyed and 29% of them said that they used the Internet for shopping at l

svetoff [14.1K]

Answer: (0.25,0.33)

Step-by-step explanation:

A 99% confidence interval for population proportion is given by:-

$\hat{p}\pm 2.576\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$ , where $\hat{p}$ = sample proportion, $n$ = sample size.

Given: $n=1025, \hat{p}=0.29$

A 99% confidence interval estimate of the proportion of adults who use the Internet for shopping:

$0.29\pm 2.576\sqrt{\dfrac{0.29(1-0.29)}{1025}}\\\\=0.29\pm 2.576\sqrt{0.00020087804878}\\\\=0.29\pm2.576(0.01417)\\\\=0.29\pm0.03650192\\\\=(0.29-0.03650192,\ 0.29+0.03650192)\\\\=(0.25349808,\ 0.32650192)$

$\approx(0.25,\ 0.33)$

Thus, a 99% confidence interval estimate of the proportion of adults who use the Internet for shopping = (0.25,0.33)

5 0

3 years ago

Pleaseeeeee help this is due today and I don’t know how to do thissss! Tug of War Activity

Hoochie [10]

Answer:

Step-by-step explanation:

7 0

3 years ago

5.<br> {wawawawawawawawawawawa}

Harrizon [31]

Answer:

35mc

Step-by-step explanation:

7 0

2 years ago

Exponential expression please help

Lelechka [254]

${3}^{ - 2} = \frac{1}{9}$

8 0

3 years ago

Read 2 more answers

Hi, can someone please answer this question? Thanks!!!

cricket20 [7]

Answer:

sorry im not so sure abut the answer

Step-by-step explanation:

.....

8 0

3 years ago