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mezya [45]
3 years ago
7

The length of a rectangular garden is 8 feet longer than its width. If the garden's perimeter is 188 feet, what is the area of t

he garden in square feet?
Mathematics
1 answer:
NemiM [27]3 years ago
3 0

Answer: The area is 2,193 square feet (2,193 ft²)

Step-by-step explanation:The rectangular garden has its sides yet unknown but what we do know is that its length is 8 feet longer than its width. If therefore the width is W, then the length would be W + 8.

The perimeter is calculated as follows;

Perimeter = 2(L + W)

We can now substitute for the values given as follows;

188 = 2(W + 8 + W)

188 = 2(2W + 8)

188 = 4W + 16

Subtract 16 from both sides of the equation

172 = 4W

Divide both sides of the equation by 4

43 = W

If the width is 43, and the length is W + 8, then length equals 43 + 8 which gives us 51

Therefore the area is calculated as follows;

Area = L x W

Area = 51 x 43

Area = 2193

The area of the rectangular garden is 2,193 square feet

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Answer:

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Step-by-step explanation:

Please find the attachment.

Let the leaning tower's be h meters tall, when it was originally built.

We can see from our attachment that the side with length 55.86 meters is hypotenuse and h is adjacent side for 4 degree angle.

Since we know that cosine relates the adjacent and hypotenuse of a right triangle.

\text{Cos}=\frac{\text{Adjacent}}{\text{Hypotenuse}}

Upon substituting our given values we will get,

\text{Cos (4)}=\frac{55.86}{h}

h=\frac{55.86}{\text{Cos (4)}}

h=\frac{55.86}{0.99756405026}

h=55.996\approx 56                      

Therefore, the leaning tower was approximately 56 meters, when it was originally built.

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