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3 years ago

Which is the axis of symmetry of a parabola with equation x^2=-4y?

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

3 0

Answer:

x = 0

Step-by-step explanation:

Given

x² = - 4y ( divide both sides by - 4 )

y = - $\frac{1}{4}$ x²

Which is a parabola opening vertically down with it's vertex at (0, 0) and symmetrical about the y- axis

Hence equation of axis of symmetry is x = 0

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$\\ \\ =-\frac { 2 }{ 24 } -\frac { 15 }{ 24 } +\frac { 36 }{ 24 } -\frac { 54 }{ 3 } +\frac { 45 }{ 2 } +9$

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