Question

Which is the axis of symmetry of a parabola with equation x^2=-4y?

Answer 1

Answer:

x = 0

Step-by-step explanation:

Given

x² = - 4y ( divide both sides by - 4 )

y = - $\frac{1}{4}$ x²

Which is a parabola opening vertically down with it's vertex at (0, 0) and symmetrical about the y- axis

Hence equation of axis of symmetry is x = 0