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AlexFokin [52]
3 years ago
11

Are the lines with equations 2x -3y = 8 and -x + 4y=2 parallel, perpendicular, or neither

Mathematics
1 answer:
skad [1K]3 years ago
3 0

Answer:

neither

Step-by-step explanation:

First, arrange the equations to fit the y=mx + b format

1. 2x - 3y = 8

y = -2/3x - 8/3

2. -x + 4y = 2

y = 1/4x + 1/2

Equations that are parallel have the same slope.

In perpendicular equations, one slope would be x and the other would be -1/x (negative reciprocal)

The equations are neither parallel nor perpendicular, so neither.

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help please! I must solve using descartes law of signs or rational root theorem. show all steps please thanks!​
wel

Answer:

x=2 or x=3

Step-by-step explanation:

x^4 - 5x^3 + 7x^2 - 5x + 6 = 0

Step 1=Factor left side of equation.

(x-2) (x-3) (x^2 + 1) = 0

Step 2=Set factors equal to 0.

x-2 = 0 or x-3 = 0 or x^2 + 1 = 0.

Answer:x=2 or x=3

4 0
3 years ago
Substitute x with (-2) and y with (-4)<br> Simplify: 5(41 - x) + {-7(y + x)} =
kkurt [141]

Answer:

257

Step-by-step explanation:

We want to evaluate:

5(41 - x) + ( - 7(y + x)

for x=-2 and y=-4.

We substitute to get:

5(41 -  - 2) + ( - 7( - 4 +  - 2)

We now simplify to get:

5(41  + 2)  - 7( - 6)

5 \times 43 + 42

215 + 42 = 257

5 0
3 years ago
It takes me 3 minutes to swim 2 laps. How long will it take me to swim 7 laps?
Rzqust [24]

Answer:

4.66666666667

Step-by-step explanation:

8 0
3 years ago
Use the quadratic formula to solve 5x^2+2x-3
Lisa [10]
Assuming it equals 0
for
ax^2+bx+c=0
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given
5x^2+2x-3=0
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b=2
c=-3

x=\frac{-2+/- \sqrt{2^2-4(5)(-3)} }{2(5)}
x=\frac{-2+/- \sqrt{4+60} }{10}
x=\frac{-2+/- \sqrt{64} }{10}
x=\frac{-2+/- 8 }{10}
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6 0
3 years ago
Which numbers are in order form least to greatest?
Anvisha [2.4K]

Answer:

B

Step-by-step explanation:

6 0
1 year ago
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